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aboverall

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[求助] 求问解释~~~

In the experimental part, details about the cell fabrication (kind of cell, separator, etc.) are missing. Moreover, it is reported that the cells were cycled at 50 microA/cm2, which is not always true (at pg. 5 cells have been cycled between 0.05 C and 2C). By the way, which theoretical capacity has been used in the C rate definition?


请问, By the way, which theoretical capacity has been used in the C rate definition?是想问什么问题?

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pedestrians

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【答案】应助回帖

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aboverall: 金币+5, ★★★很有帮助 2012-09-13 15:59:36
就是你的容量C是在多大放电电流下确定的,这样才能知道0.05C 和2C是多大的电流。
2楼2012-09-13 14:09:14
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aboverall

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引用回帖:
2楼: Originally posted by pedestrians at 2012-09-13 14:09:14
就是你的容量C是在多大放电电流下确定的,这样才能知道0.05C 和2C是多大的电流。

谢谢你~
3楼2012-09-13 15:59:53
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pedestrians

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aboverall: 金币+3, ★★★很有帮助 2012-09-14 09:48:36
C一小时放电容量,对应一个电流密度i,2C就是以2i的电流放电 ;0.5C就是以0.5i的电流放电,我不知道这样理解对不对,望共同探讨
4楼2012-09-13 22:47:55
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aboverall

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引用回帖:
4楼: Originally posted by pedestrians at 2012-09-13 22:47:55
C一小时放电容量,对应一个电流密度i,2C就是以2i的电流放电 ;0.5C就是以0.5i的电流放电,我不知道这样理解对不对,望共同探讨

对于钴酸锂而言,1C对应的放电容量如果是140mAhg-1,那么电流就要是140mAg-1,对吧??

0.5C,电流就要是70mAg-1


这样理解对吗?
5楼2012-09-14 09:53:44
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pedestrians

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我认为是这样的,

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6楼2012-09-14 19:43:45
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aboverall

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引用回帖:
6楼: Originally posted by pedestrians at 2012-09-14 19:43:45
我认为是这样的,

谢谢~~~
7楼2012-09-15 09:25:19
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