2Â¥: Originally posted by acmuser at 2012-05-22 15:46:32:
domain and boundary condition?

4Â¥: Originally posted by leedobb at 2012-05-22 15:59:01:
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7Â¥: Originally posted by acmuser at 2012-05-23 00:16:30:
If you do separation of variables, u=X(x)Y(y), you could obtain Y(y)=exp(iky), and X"(x)/X(x) = mexp(2x)+k^2,
by linearity, we can consider X"(x)/X(x) = m exp(2x) and X"(x)/X(x) separ

7Â¥: Originally posted by acmuser at 2012-05-23 00:16:30:
If you do separation of variables, u=X(x)Y(y), you could obtain Y(y)=exp(iky), and X"(x)/X(x) = mexp(2x)+k^2,
by linearity, we can consider X"(x)/X(x) = m exp(2x) and X"(x)/X(x) separ