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Jackie2011

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2Â¥2012-05-13 20:46:39
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ÒýÓûØÌû:
2Â¥: Originally posted by Jackie2011 at 2012-05-13 20:46:39:
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3Â¥2012-05-13 21:24:33
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·ÆÄã²»°®

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ÒýÓûØÌû:
2Â¥: Originally posted by Jackie2011 at 2012-05-13 20:46:39:
ͨ·ÖºóÀûÓÃÌõ¼þ,»¯³Éa+b+cµÄ¶þ´Î·½³Ì,ÔÙÓÃÅб𷨿ÉÖ¤!

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4Â¥2012-05-13 21:51:19
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acmuser

Òø³æ (СÓÐÃûÆø)

Apparently when a=b=1, c=0, the inequality takes value 2.5, which suggests that a,b,c are not symmetric in the problem.


5Â¥2012-05-13 22:19:53
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acmuser

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Apparently when a=b=1, c=0, the inequality takes value 2.5, which suggests that a,b,c are not symmetric in the problem.


6Â¥2012-05-13 22:23:29
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·ÆÄã²»°®

Òø³æ (³õÈëÎÄ̳)

ÒýÓûØÌû:
5Â¥: Originally posted by acmuser at 2012-05-13 22:19:53:
Apparently when a=b=1, c=0, the inequality takes value 2.5, which suggests that a,b,c are not symmetric in the problem.
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7Â¥2012-05-14 11:54:41
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acmuser

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
7Â¥: Originally posted by ·ÆÄã²»°® at 2012-05-14 11:54:41:
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for competition? all the places using derivatives can be justified by elementary calculation. The point is, the minimum takes value at either a=b or b=c, then check it directly.
8Â¥2012-05-14 16:32:48
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