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monitor2885

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[求助] 方程组的解怎么画图呢?

怎么用matlab编程,画出y1,y2,y3随着x变化图。y1,y2,y3三条曲线画在一张图里。
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dbb627

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【答案】应助回帖

感谢参与,应助指数 +1
monitor2885(金币+10): ★★★★★最佳答案 啊,先化简方程啊。 2012-02-24 13:35:50
xiegangmai(金币+2, 专家考核): 谢谢应助! 2012-02-24 23:50:44
[y1,y2,y3]=solve('10^(x-6.77)=y1/y2','10^(2.17-x)=y3/y2','y1+y2+y3=1','y1,y2,y3')

y1 =

(1.1481536214968827515462246116628*10.0^(2.0*x))/(6760829.7539198177105899194961757*10.0^x + 1.1481536214968827515462246116628*10.0^(2.0*x) + 1000000000.0)


y2 =

(6760829.7539198177105899194961757*10.0^x)/(6760829.7539198177105899194961757*10.0^x + 1.1481536214968827515462246116628*10.0^(2.0*x) + 1000000000.0)


y3 =

1000000000.0/(6760829.7539198177105899194961757*10.0^x + 1.1481536214968827515462246116628*10.0^(2.0*x) + 1000000000.0)
知道表达式,画图不是什么问题吧
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
2楼2012-02-24 08:27:34
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monitor2885

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引用回帖:
楼: Originally posted by dbb627 at 2012-02-24 08:27:34:
[y1,y2,y3]=solve('10^(x-6.77)=y1/y2','10^(2.17-x)=y3/y2','y1+y2+y3=1','y1,y2,y3')

y1 =

(1.1481536214968827515462246116628*10.0^(2.0*x))/(6760829.7539198177105899194961757*10.0^x + 1.1481536 ...

请问,怎么把数字格式改变一下呢?科学计数法,小数点后保留三位。谢谢
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3楼2012-02-27 12:27:14
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