Cu k-beta ray (λkβ=0.1392 nm).
Bragg's law, 2dsinθ=nλ.
the angel where the peak of the Cu k-beta ray by the Si (400) planes should be located at 2θ=2×arcsin[0.1392/(2×0.1357)]=61.713 (degree), which is almost the same as that observed from your figure.
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