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木虫 (著名写手)

[求助] 求助文献里的一段解释

The crystal structure of as-prepared graphene was characterized by XRD. From curve a in Fig. 3, the feature reflection peak of graphite located on the 2 angle of ∼26.6◦ (0 0 1) is observed with an interlayer spacing of 0.34 nm. The sharp and very intense basal reflection indicates the highly crystalline nature of graphite. This is in sharp contract to the GO (curve b). After oxidation and exfoliation, the diffraction peak of dried GO appears at 10.8◦ (0 0 2), indicating an estimated interlay space of 0.85 nm, quite similar to those reported elsewhere [21,27]. This value (0.85 nm) is much larger than the space (0.34 nm) of pristine graphite, attributed to the introduction of oxygenated functional groups on carbon sheets.
In the other hand, after the subsequent reduction, the diffraction peak disappeared (curve c) even when the y-axis was changed to a logarithm scale (inset of Fig. 3), confirming the great reduction of oxygenated groups and the high exfoliating degree of the layered graphene [28].求助下划线那句是怎么算出来的,0.34nm???

XRD
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木虫 (著名写手)

引用回帖:
11楼: Originally posted by xmcx at 2011-11-03 22:30:37:
布拉格方程2d*sinθ=波长
用jade searchmatch 直接可以测出

能说的再详细一点吗?装了半天JADE 5.0。还是不咋会用。。。
12楼2011-11-04 10:43:59
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木虫 (著名写手)

自己顶起,希望被懂得人看到。。。帮忙解释一下
2楼2011-11-02 16:32:11
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木虫 (著名写手)

层间距0.34纳米,怎么算出来的???用什么数据得到的?用XRD?
3楼2011-11-02 16:34:11
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huahua1216

至尊木虫 (文坛精英)

布拉格方程的晶面间距d是不是就是这个层间距啊
4楼2011-11-02 16:37:50
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