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wuzetian

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2Â¥2011-04-04 19:25:07
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zxz.1982

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Charles911

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3Â¥2011-04-04 20:49:34
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chihaijun

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[ Last edited by chihaijun on 2011-4-4 at 23:31 ]
4Â¥2011-04-04 22:20:05
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wuzetian

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5Â¥2011-04-04 22:23:07
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JLU_chem_man

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Äã¼ÈÈ»»³ÒÉ473.2ÊÇ945.5µÄË«µçºÉ·å£¿ÎªÊ²Ã´²»°ÑËûÃÇ´òËé¿´¿´ÄØ£¿¿´¿´ÏàÓ¦µÄÐòÁÐÀë×ÓÄÜ·ñ¶¼¶ÔÓ¦Éϰ¡£¿ÄãÕâ¸öëĶιÀ¼ÆÒ²¾ÍÔÚ10ëÄ×óÓÒ£¬Ë«µçºÉ»¹ÊǺÜÓпÉÄܵġ£¶à¹Û²ìÏÂÍ¬Î»ËØ·å°É£¡
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6Â¥2011-04-05 14:11:21
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boringboring

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Сľ³æ: ½ð±Ò+0.5, ¸ø¸öºì°ü£¬Ð»Ð»»ØÌû
Your sample's molecular monoisotopic mass is 944.5.
(M+H)+, A0: 945.5 (with zero C being C13)
A1:  946.5  (with 1 C being C13)
A2:  947.5  (with 2 C being C13), intensity ratio of A0:A1:A2 can yield number of carbons in your peptide.
(M+2H)++, A0: (944.5+2)/2=473.25
A1: 473.8=473.25+0.5
A2:  474.3=473.8+0.5
945.5-657.4=loss of mass 288 fragment, which is correspondent to its doubly charge 473.2-329.2.
3.98e3 is the ion count of the most abundant peak at 473.2, 100%.
7Â¥2013-07-24 05:29:46
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