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passionfly

金虫 (小有名气)

[交流] 【求助】用最小二乘法求解线性方程组的Fortran代码 已有4人参与

For a standard linear system, y(n*1)=A(n*n)x(n*1)

If y is exact and A is well-conditioned, it is easy to calculate x.

However, if y has some disturbances or some errors, at the same time, A matrix is ill-conditioned. It is difficult to accurately obtain vector x. Alternatively, we can measure more components of y (becomes m*1, where m>n) and use the least square method to calculate the approximate x vector.

It is a common problem so I guess there should be some ready-to-use Fortran codes. Anybody knows where can I find this algorithms or codes? Any advice or suggestion is welcomed!

Thank you very much and with best wishes,
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貳零壹壹

铜虫 (小有名气)

这个对我有难度,呵呵
2楼2010-10-30 20:04:27
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Ptolomaeus

铁杆木虫 (正式写手)

★ ★
小木虫(金币+0.5):给个红包,谢谢回帖交流
cqsmath(金币+1):谢谢分享! 2010-11-08 21:40:44
LAPACK里有成熟的代码
http://www.netlib.org/lapack/
LAPACK是当今计算数学界最权威的软件包,实现了几乎所有成熟的数值代数算法(F和C)。
3楼2010-11-02 23:00:14
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passionfly

金虫 (小有名气)

呵呵,非常感谢!
4楼2010-11-07 11:22:30
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peterflyer

木虫之王 (文学泰斗)

peterflyer


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小木虫: 金币+0.5, 给个红包,谢谢回帖
现在用的Fortran是哪个版本的?老夫学的时候还是Fortran 77呢,已经是将近30年前的事了。
5楼2013-11-01 16:11:58
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