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[ Last edited by iris19860908 on 2010-8-23 at 16:34 ]
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iris19860908(½ð±Ò+4):ÕæµÄºÜÓаïÖú £¬Ð»Ð»Äã 2010-08-24 08:52:15
tangjy(½ð±Ò+2):¸ÐлӦÖú£¡ 2010-08-28 11:19:43
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Originally posted by iris19860908 at 2010-08-23 16:22:41:
¸÷λ³æÓÑ£¬ÎÒÔÚ×öÓÐ¹ØÆøÌå´ß»¯·´Ó¦µÄ¹ý³ÌÖÐÏëÒªµÃµ½·´Ó¦µÄ»î»¯ÄÜ£¬¼´ÔÚ²»Í¬ÖÖ²ÄÁÏÉÏ´¦Àí·´Ó¦µÄ»î»¯ÄÜ£¬¸Ä±ä·´Ó¦Î¶ȵõ½Ò»Ð©Ïà¹ØµÄ²»Í¬²ÄÁÏ·´Ó¦µÄÊý¾Ý£¬µ«ÊÇÈçºÎµÃµ½»î»¯ÄÜÄØ£¿ÊÇͨ¹ýÈí¼þ»¹ÊÇÊÖËãÄØ£¿
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according to the question, you want to obtain the reaction active energy.  if you want to know the adsorption behavior, then the adsorption energy could be done by soprtion experiments.

the basice equation is :

r=d[c]/dt, Here c is the the reactant concentration, and t is the contact time.

as we know the concentraiont change with the raction time, it is
c=c0(1-x) herein the x is conversion,
so d[c]=C0d[x]
t=W/F,

from those, then you could get the rate equation

r=C0 d[x]/D[W/F]
normally, the weight the catalyst dosen't change, so, it could be obtained by changing the flow rate.

at one temperature, reaction rate is r=C0 x/[W/G]

according to Arrhinius equation, r=a exp(-Ea/RT)
Ln(r)=-Ea/RT

plot the r as a function of reaction temperature, normally, you could get a line, from the slope, you could calculate the active energy.
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