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小木虫(金币+0.5):给个红包，谢谢回帖交流
javeey(金币+2):谢谢参与交流 2010-06-20 08:08:15
Doctorcbw(金币+20):楼主要求为了感谢您 对他问题的帮助，请我代奖励金币20 2010-06-20 11:03:51
Doctorcbw(数学EPI+1):谢谢您热心的回答！ 2010-06-20 11:04:54
这种题目比较烦人，
题目中可能还少一个条件，费用和货物量的关系?
方法很简单，先求全排列，再切割每个排列
我算的答案是：
费用：25866720
路线是：3 6 -------- 4 2 1 5 ，其中4，6是枢纽
源程序：
clear;clc;
NC = 6;
huo_f = 'E:\兴趣学习\interesting_pro\航空枢纽选择选址\huoliang.txt';
dis_f = 'E:\兴趣学习\interesting_pro\航空枢纽选择选址\distance.txt';
quan_pai = perms( 1:NC );
[huo(:,1) huo(:,2) huo(:,3) huo(:,4) huo(:,5) huo(:,6) ] = textread(huo_f,'%f %f %f %f %f %f ');
[dis(:,1) dis(:,2) dis(:,3) dis(:,4) dis(:,5) dis(:,6) ] = textread(dis_f,'%f %f %f %f %f %f ');
[len1 hg] = size(quan_pai);
min_val = 1e100;
sequ(1:NC) = 0;
cut_p = 1;
for i = 1:len1
a = quan_pai( i, : );
for j = 1:NC-1
[ min_val sequ cut_p ] = get_min_seq( a, j, min_val, sequ, huo, dis, NC, cut_p );
end
end
子程序：
function [ min_val, sequ, cut_p ] = get_min_seq( a, j, min_val, sequ, huo, dis, NC, cut_p );
% get 1st part
tot_huo = 0;
for i = 1:j-1
tot_huo = tot_huo + sum( huo( a(i), : ) ) + sum( huo( :, a(i) ) );
end
tot_fee1 = tot_huo * dis( a(i), a(j) );
% get 2nd part
tot_huo = 0;
for i = j+2:NC
tot_huo = tot_huo + sum( huo( a(i), : ) ) + sum( huo( :, a(i) ) );
end
tot_fee2 = tot_huo * dis( a(i), a(j+1) );
% get mid part
tot_huo = 0;
for i = 1:j
for k = j+1:NC
tot_huo = tot_huo + huo( a(i), a(k) ) + huo( a(k), a(i) );
end
end
tot_fee3 = 0.8*tot_huo * dis( a(j), a(j+1) );
tot_fee = tot_fee1 + tot_fee2 + tot_fee3;
if tot_fee < min_val
min_val = tot_fee;
sequ = a;
cut_p = j;
elseif tot_fee == min_val
[len2 kj] = size(sequ);
sequ( len2+1, = a;
cut_p(len2+1) = j;
else
min_val = min_val;
sequ = sequ;
cut_p = cut_p;
end
数据：
distance.txt
0 945 605 4667 4749 4394
945 0 866 3726 3806 3448
605 866 0 4471 4541 4152
4667 3726 4471 0 109 415
4749 3806 4541 109 0 431
4394 3448 4152 415 431 0
huoliang.txt
0 500 1000 300 400 1500
1500 0 250 630 360 1140
400 510 0 460 320 490
300 600 810 0 820 310
400 100 420 730 0 970
350 1020 260 580 380 0
[ Last edited by zxczxc0417 on 2010-6-20 at 00:29 ] |
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