| 查看: 2097 | 回复: 12 | ||
| 当前只显示满足指定条件的回帖,点击这里查看本话题的所有回帖 | ||
[求助]
求大神帮忙翻译一下文献中的英文。用谷歌翻译的不是很懂已有3人参与
|
||
|
Considering the strong π-conjugated effect of the rigid coplanar Py 2 TTz ligand and d 10 electron configuration of central metal ions, compounds 1 and 2 are likely to exhibit good fluorescent properties. Thus, the fluorescent properties of free ligand and compounds 1 and 2 were investigated. As shown in Figure S7, the free ligand Py 2 TTz exhibits two emission peaks at 440 nm and 451 nm upon excitation at 413 nm in the solid state, which can be assigned to π*-π transition. 68-69 Upon excitation at 414 nm for compound 1 and 417 nm for compound 2, the emission peaks of compounds 1 and 2 in powder samples appear at 453 nm and 518 nm, respectively. Compared with the free ligand Py 2 TTz, the emission peak of compound 1 is slightly red shifted, which can be attributed to metal perturbed emission of ligand. However, compound 2 displays a large red shift of 67 nm, which may be assigned to the ligand- to-metal charge transfer (LMCT). 70-71 |
» 猜你喜欢
MOF合成
已经有0人回复
请问各位大佬ACS投稿状态这样是成功了吗?
已经有6人回复
无机化学论文润色/翻译怎么收费?
已经有214人回复
【答案】应助回帖
|
考虑刚性共平面的py2ttz 配体和 d10 电子中心金属离子的强共轭效应, 化合物1和2可能展现出良好的荧光性能。因此, 我们研究了配体和 化合物1和2 的荧光性质。如图 S7 所示, 当激发波长是413 纳米的时候,固态荧光光谱显示配体Py2ttz在440 纳米和451纳米 有两个发射峰, 这个两个峰源于反键的Pi 轨道到Pi轨道的电子跃迁。当用 414 nm 激发化合物1和 417 nm激发化合物 2 的时候, 化合物1和2的发射光波长分别在453 纳米和518 纳米。与单独的配体相比,化合物1 的发射光红移的一点点,主要是由于金属对配体的影响造成的。但是,化合物2的67纳米的红移是由配体到金属的跃迁引起的。 |

12楼2018-11-14 06:39:15














回复此楼