clc,clear
x=0:0.01:1;
for i=1:100;
t(i)=0.01*(i-1);
H0(i)=1+0.3*sin(30*t(i)) ;
H=(1+0.9)*(0.8+0.2*(1-x).^2)*H0(i)/(0.8+0.2*(1-x).^2+0.9)   
end

2楼: Originally posted by Biyago at 2016-01-05 12:24:57
如果运行没错的话，那个结果应该是i=100的结果

3楼: Originally posted by smartliang at 2016-01-05 12:33:54
因为H是个数值变量，不是数组，只能存一个数，循环完就是最后一个数

7楼: Originally posted by getengqing at 2016-01-05 13:45:41
你这样肯定是也值啊，你把最后的除号/前面见一个.就可以了！！！

7楼: Originally posted by getengqing at 2016-01-05 13:45:41
你这样肯定是也值啊，你把最后的除号/前面见一个.就可以了！！！

9楼: Originally posted by m76acxb at 2016-01-05 16:17:29
金币点错了，不好意思呀，到时看能不能给一点...