[求助] 求极限 已有2人参与

4楼: Originally posted by --power at 2015-11-28 09:49:09
请问是这样吗？
\ln \lim_{x\to \infty} (\frac{1}{x}+2^{{1}{x}})^x
=\lim_{x\to \infty}\ln(\frac{1}{x}+2^{{1}{x}})^x
=\lim_{x\to \infty}x\ln(\frac{1}{x}+2^{{1}{x}})
=\lim_{x\to \infty}\frac{\l ...

3楼: Originally posted by xiangxiang32 at 2015-11-28 09:26:11
取自然对数

5楼: Originally posted by xiangxiang32 at 2015-11-28 10:08:00
就是这个方法
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