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feixiaolin
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To fit a Weibull distribution to these data, notice that the CDF for the Weibull is p = Pr{X <= x} = 1 - exp(-(x/a)^b). Transforming that to log(a) + log(-log(1-p))*(1/b) = log(x) again gives a linear relationship, this time between log(-log(1-p)) and log(x). We can use least squares to fit a straight line on the transformed scale using p and x from the ECDF, and the slope and intercept of that line lead to estimates of a and b. È˼ÒÒѾ½²Çå³þÀ² |
2Â¥2015-11-03 20:26:57
3Â¥2015-11-03 21:12:27
feixiaolin
ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)
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4Â¥2015-11-03 23:08:53
5Â¥2015-11-04 13:52:57














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