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K1=[H2CO3]/([CO2][H2O])---->>K1'=K1[H2O]=[H2CO3]/[CO2]=2.5*10^-3
K2=[H+][HCO3-]/[H2CO3]=1.74*10^-4 = K1'[CO2]
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[H+]=[HCO3-]=1.23*10^-4
7Â¥2015-10-13 23:40:56
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fengyang0830

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wuyan0702

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2Â¥: Originally posted by ¹ÈÖÐÃ÷ at 2015-10-13 17:58:09
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3Â¥: Originally posted by fengyang0830 at 2015-10-13 18:39:46
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wuyan0702

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7Â¥: Originally posted by fengyang0830 at 2015-10-13 23:40:56
K1=/()---->>K1'=K1=/=2.5*10^-3
K2=/=1.74*10^-4 = K1'
K3=/<<K2, Kw==10^-14<<K2,¹Ê¶øÈ«²¿ºöÂÔ¡£
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7Â¥: Originally posted by fengyang0830 at 2015-10-13 23:40:56
K1=/()---->>K1'=K1=/=2.5*10^-3
K2=/=1.74*10^-4 = K1'
K3=/<<K2, Kw==10^-14<<K2,¹Ê¶øÈ«²¿ºöÂÔ¡£
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K1=[H2CO3]/([CO2][H2O])---->>K1'=K1[H2O]=[H2CO3]/[CO2]=2.5*10^-3
K2=[H+][HCO3-]/[H2CO3]=1.74*10^-4 =[H+][HCO3-]/K1'[CO2]
ÓÖÓÉÓÚK3=[H+][CO32-]/[HCO3-]<<K2, Kw=[H+][OH-]=10^-14<<K2,¹Ê¶øÈ«²¿ºöÂÔ¡£
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µçºÉƽºâʽ£º[H+]=2[CO32-]+[HCO3-]+[0H-]=[HCO3-]
CÔªËØÆ½ºâʽ£º
SCO2=[CO2]+[CO32-]+[HCO3-]+[H2CO3]
       =[CO2]+[HCO3-]+[H2CO3]
       =[CO2]+[HCO3-]+K1'[CO2]
¼´[CO2]=(SCO2-[HCO3-])/(1+k1')=(SCO2-[H+])/(1+k1')
ÓÉÓÚk1'=2.5*10^-3 <<1,¹Ê¶øºöÂÔ£¬´Ó¶ø[CO2]=(SCO2-[H+])
ÓÚÊÇK2=[H+][HCO3-]/[H2CO3]= [H+][HCO3-]/K1'[CO2] =[H+][HCO3-]/ K1'(SCO2-[H+])
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[H+]^2=K1'K2(SCO2-[H+])=2.5*10^-3 *1.74*10^-4*(0.035-[H+])=4.25*10^-7(0.035-[H+])

[H+]=[HCO3-]=1.22*10^-4
9Â¥2015-10-15 08:34:50
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fengyang0830

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ÒýÓûØÌû:
9Â¥: Originally posted by fengyang0830 at 2015-10-15 08:34:50
Óеã覴ã¬ÐÞÕýһϣº
K1=/()---->>K1'=K1=/=2.5*10^-3
K2=/=1.74*10^-4 =/K1'
ÓÖÓÉÓÚK3=/<<K2, Kw==10^-14<<K2,¹Ê¶øÈ«²¿ºöÂÔ¡£
¼´<<ºÍ<<£¬¿ÉÒÔºöÂÔ¡£ÄÇô£º
µçºÉƽºâʽ£º=2++ ...

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K1=[H2CO3]/([CO2][H2O])---->>K1'=K1[H2O]=[H2CO3]/[CO2]=2.5*10^-3
K2=[H+][HCO3-]/[H2CO3]=1.74*10^-4 =[H+][HCO3-]/K1'[CO2]
ÓÖÓÉÓÚK3=[H+][CO32-]/[HCO3-]<<K2, Kw=[H+][OH-]=10^-14<<K2,¹Ê¶øÈ«²¿ºöÂÔ¡£
¼´[CO32-]<<[HCO3-]ºÍ[0H-]<<[H+]£¬¿ÉÒÔºöÂÔ¡£ÄÇô£º
µçºÉƽºâʽ£º[H+]=2[CO32-]+[HCO3-]+[0H-]=[HCO3-]
CÔªËØÆ½ºâʽ£º
SCO2=[CO2]+[CO32-]+[HCO3-]+[H2CO3]
       =[CO2]+[HCO3-]+[H2CO3]
       =[CO2]+[HCO3-]+K1'[CO2]
¼´[CO2]=(SCO2-[HCO3-])/(1+k1')=(SCO2-[H+])/(1+k1')
ÓÉÓÚk1'=2.5*10^-3 <<1,¹Ê¶øºöÂÔ£¬´Ó¶ø[CO2]=(SCO2-[H+])
ÓÚÊÇK2=[H+][HCO3-]/[H2CO3]= [H+][HCO3-]/K1'[CO2] =[H+][HCO3-]/ K1'(SCO2-[H+])
½áºÏµçºÉƽºâʽ[H+]=[HCO3-]£¬ÓÐ[H+][HCO3-]/(SCO2-[H+])=[H+]^2/(SCO2-[H+])=K1'K2,¼´
[H+]^2=K1'K2(SCO2-[H+])=2.5*10^-3 *1.74*10^-4*(0.035-[H+])=4.35*10^-7(0.035-[H+])

[H+]=[HCO3-]=1.23*10^-4

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10Â¥2015-10-15 08:40:14
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