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皓小天木虫之王 (职业作家)
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[求助]
编程模式下1stopt如何使用积分拟合 已有1人参与
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编程模式下1stopt如何拟合下面的代码,版本6.0 要求:在编程模式下,正确的可执行代码和正确的运行结果 @dingd @月只蓝 Parameter a,b,c,d; Variable x,y; StartProgram [Pascal]; Procedure MainModel; var i:integer; t:double; begin for i:=0 to DataLength-1 do begin y:=a-b*exp(-c*x^d)*int((t+x),t:=0.1,c); end; End; EndProgram; Data; 0.05 0.13 0.15 0.13 0.25 0.19 0.35 0.34 0.45 0.53 0.55 0.71 0.65 1.06 0.75 1.6 0.85 1.64 0.95 1.83 1.05 2.09 1.15 2.05 1.25 2.13 1.35 2.12 1.45 2.09 运行结果: \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\integrateunit_(1) \1stopt 6.0\lib\integrateunit_(5) \1stopt 6.0\lib\integrateunit_(7) \1stopt 6.0\lib\integrateunit_(16) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\integrateinfunit_(1) \1stopt 6.0\lib\integrateinfunit_(5) \1stopt 6.0\lib\integrateinfunit_(7) \1stopt 6.0\lib\integrateinfunit_(10) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(6) \1stopt 6.0\lib\fitdll(29) error: undeclared identifier: 'x' \1stopt 6.0\lib\fitdll(248) error: expression expected but ';' found \1stopt 6.0\lib\fitdll(249) error: expression expected but ';' found \1stopt 6.0\lib\fitdll(320) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(323) error: undeclared identifier: '3' \1stopt 6.0\lib\fitdll(328) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(331) error: undeclared identifier: '4' \1stopt 6.0\lib\fitdll(336) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(339) error: undeclared identifier: '5' \1stopt 6.0\lib\fitdll(344) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(348 error: undeclared identifier: '6' \1stopt 6.0\lib\fitdll(352) error: statement expected, but expression of type 'double' found \1stopt 6.0\lib\fitdll(25) error: label declared and referenced, but not set: '30' \1stopt 6.0\lib\fitdll(361) error: declaration expected but identifier 'temdy__i__' found \1stopt 6.0\lib\fitdll(365) error: declaration expected but identifier 'temdy__i__' found \1stopt 6.0\lib\fitdll(368) error: '.' expected but ';' found \1stopt 6.0\lib\fitdll(372) warning: text after final 'end.' - ignored by compiler \1stopt 6.0\lib\fitdll(392) Compile failed, check your program codes please! |
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编程模式下1stopt如何使用积分拟合
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皓小天
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5楼2015-10-09 10:09:46
dingd
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2楼2015-10-06 21:54:16
皓小天
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你好, 我按照你的代码进行了运行,仍然出错,代码如下: Parameter a,b,c,d; Variable x,y; StartProgram [Pascal]; Procedure MainModel; var i:integer; t:double; begin for i:=0 to DataLength-1 do begin y:=a-b*exp(-c*x^d)*int((t+x),t=0.1,c); end; End; EndProgram; Data; 0.05 0.13 0.15 0.13 0.25 0.19 0.35 0.34 0.45 0.53 0.55 0.71 0.65 1.06 0.75 1.6 0.85 1.64 0.95 1.83 1.05 2.09 1.15 2.05 1.25 2.13 1.35 2.12 1.45 2.09 结果如下: \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(1) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\integrateunit_(1) \1stopt 6.0\lib\integrateunit_(5) \1stopt 6.0\lib\integrateunit_(7) \1stopt 6.0\lib\integrateunit_(16) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\integrateinfunit_(1) \1stopt 6.0\lib\integrateinfunit_(5) \1stopt 6.0\lib\integrateinfunit_(7) \1stopt 6.0\lib\integrateinfunit_(10) \1stopt 6.0\lib\fitdll(4) \1stopt 6.0\lib\fitdll(6) \1stopt 6.0\lib\fitdll(31) warning: return value of function 'func__i__' might be undefined \1stopt 6.0\lib\fitdll(320) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(323) error: undeclared identifier: '3' \1stopt 6.0\lib\fitdll(328) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(331) error: undeclared identifier: '4' \1stopt 6.0\lib\fitdll(336) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(339) error: undeclared identifier: '5' \1stopt 6.0\lib\fitdll(344) error: missing operator or semicolon \1stopt 6.0\lib\fitdll(348) error: undeclared identifier: '6' \1stopt 6.0\lib\fitdll(352) error: statement expected, but expression of type 'double' found \1stopt 6.0\lib\fitdll(25) error: label declared and referenced, but not set: '30' \1stopt 6.0\lib\fitdll(361) error: declaration expected but identifier 'temdy__i__' found \1stopt 6.0\lib\fitdll(365) error: declaration expected but identifier 'temdy__i__' found \1stopt 6.0\lib\fitdll(368) error: '.' expected but ';' found \1stopt 6.0\lib\fitdll(372) Warning: Text after final 'END.' - ignored by compiler \1stopt 6.0\lib\fitdll(392) Compile failed, check your program codes please! |

3楼2015-10-06 22:11:47
dingd
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4楼2015-10-09 10:07:41













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