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[求助] 编程模式下1stopt如何使用积分拟合已有1人参与

编程模式下1stopt如何拟合下面的代码，版本6.0
要求：在编程模式下，正确的可执行代码和正确的运行结果
@dingd @月只蓝
Parameter a,b,c,d;
Variable x,y;
StartProgram [Pascal];
Procedure MainModel;
var
i:integer;
t:double;
begin
for i:=0 to DataLength-1 do
begin
y:=a-b*exp(-c*x^d)*int((t+x),t:=0.1,c);
end;
End;
EndProgram;
Data;
0.05       0.13
0.15       0.13
0.25       0.19
0.35       0.34
0.45       0.53
0.55       0.71
0.65       1.06
0.75       1.6
0.85       1.64
0.95       1.83
1.05       2.09
1.15       2.05
1.25       2.13
1.35       2.12
1.45       2.09
运行结果：
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\integrateunit_(1)
\1stopt 6.0\lib\integrateunit_(5)
\1stopt 6.0\lib\integrateunit_(7)
\1stopt 6.0\lib\integrateunit_(16)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\integrateinfunit_(1)
\1stopt 6.0\lib\integrateinfunit_(5)
\1stopt 6.0\lib\integrateinfunit_(7)
\1stopt 6.0\lib\integrateinfunit_(10)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(6)
\1stopt 6.0\lib\fitdll(29) error: undeclared identifier: 'x'
\1stopt 6.0\lib\fitdll(248) error: expression expected but ';' found
\1stopt 6.0\lib\fitdll(249) error: expression expected but ';' found
\1stopt 6.0\lib\fitdll(320) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(323) error: undeclared identifier: '3'
\1stopt 6.0\lib\fitdll(328) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(331) error: undeclared identifier: '4'
\1stopt 6.0\lib\fitdll(336) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(339) error: undeclared identifier: '5'
\1stopt 6.0\lib\fitdll(344) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(348
error: undeclared identifier: '6'
\1stopt 6.0\lib\fitdll(352) error: statement expected, but expression of type 'double' found
\1stopt 6.0\lib\fitdll(25) error: label declared and referenced, but not set: '30'
\1stopt 6.0\lib\fitdll(361) error: declaration expected but identifier 'temdy__i__' found
\1stopt 6.0\lib\fitdll(365) error: declaration expected but identifier 'temdy__i__' found
\1stopt 6.0\lib\fitdll(368) error: '.' expected but ';' found
\1stopt 6.0\lib\fitdll(372) warning: text after final 'end.' - ignored by compiler
\1stopt 6.0\lib\fitdll(392)
Compile failed, check your program codes please!

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编程模式下1stopt如何使用积分拟合已经有2人回复

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1楼 2015-10-06 20:56:43

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dingd

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【答案】应助回帖

★ ★
感谢参与，应助指数 +1
ben_ladeng: 金币+2, 辛苦了 2015-10-09 07:24:51

改成如下试试：

CODE:

Parameter a,b,c,d;

Variable x,y;

StartProgram [Pascal];

Procedure MainModel;

var

i:integer;

t:double;

begin

for i:=0 to DataLength-1 do

begin

y[i]:=a-b*exp(-c*x[i]^d)*int((t+x[i]),t=0.1,c);

end;

End;

EndProgram;

Data;

0.05        0.13

0.15        0.13

....

赞一下

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2楼2015-10-06 21:54:16

已阅回复此楼关注TA 给TA发消息送TA红花 TA的回帖

皓小天

木虫之王 (职业作家)

应助: 19 (小学生)
贵宾: 0.1
金币: 76016.6
散金: 502
红花: 137
帖子: 3801
在线: 869小时
虫号: 1864745
注册: 2012-06-19
性别: GG
专业: 力学中的基本问题和方法

引用回帖:

2楼: Originally posted by dingd at 2015-10-06 21:54:16
改成如下试试：

Parameter a,b,c,d;
Variable x,y;
StartProgram ;
Procedure MainModel;
var
i:integer;
t:double;
begin
for i:=0 to DataLength-1 do
begin
y:=a-b*exp(-c*x^d)*int((t+x),t=0.1,c) ...

你好，
我按照你的代码进行了运行，仍然出错，代码如下：
Parameter a,b,c,d;
Variable x,y;
StartProgram [Pascal];
Procedure MainModel;
var
i:integer;
t:double;
begin
for i:=0 to DataLength-1 do
begin
y:=a-b*exp(-c*x^d)*int((t+x),t=0.1,c);
end;
End;
EndProgram;
Data;
0.05       0.13
0.15       0.13
0.25       0.19
0.35       0.34
0.45       0.53
0.55       0.71
0.65       1.06
0.75       1.6
0.85       1.64
0.95       1.83
1.05       2.09
1.15       2.05
1.25       2.13
1.35       2.12
1.45       2.09
结果如下：
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(1)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\integrateunit_(1)
\1stopt 6.0\lib\integrateunit_(5)
\1stopt 6.0\lib\integrateunit_(7)
\1stopt 6.0\lib\integrateunit_(16)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\integrateinfunit_(1)
\1stopt 6.0\lib\integrateinfunit_(5)
\1stopt 6.0\lib\integrateinfunit_(7)
\1stopt 6.0\lib\integrateinfunit_(10)
\1stopt 6.0\lib\fitdll(4)
\1stopt 6.0\lib\fitdll(6)
\1stopt 6.0\lib\fitdll(31) warning: return value of function 'func__i__' might be undefined
\1stopt 6.0\lib\fitdll(320) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(323) error: undeclared identifier: '3'
\1stopt 6.0\lib\fitdll(328) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(331) error: undeclared identifier: '4'
\1stopt 6.0\lib\fitdll(336) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(339) error: undeclared identifier: '5'
\1stopt 6.0\lib\fitdll(344) error: missing operator or semicolon
\1stopt 6.0\lib\fitdll(348) error: undeclared identifier: '6'
\1stopt 6.0\lib\fitdll(352) error: statement expected, but expression of type 'double' found
\1stopt 6.0\lib\fitdll(25) error: label declared and referenced, but not set: '30'
\1stopt 6.0\lib\fitdll(361) error: declaration expected but identifier 'temdy__i__' found
\1stopt 6.0\lib\fitdll(365) error: declaration expected but identifier 'temdy__i__' found
\1stopt 6.0\lib\fitdll(368) error: '.' expected but ';' found
\1stopt 6.0\lib\fitdll(372)
Warning: Text after final 'END.' - ignored by compiler
\1stopt 6.0\lib\fitdll(392)
Compile failed, check your program codes please!