7楼: Originally posted by 080301211 at 2015-07-15 08:34:47
第一楼大神的主意很不错，可惜矩阵不可逆，无法消Y，期待各位大神的进一步指点！
:arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm::arm:
:arm::arm::arm::arm::arm::arm::arm::arm: ...

2楼: Originally posted by feixiaolin at 2015-07-13 23:15:29
A^T*AY=A^T*CX，解出Y
B^T*BY=B^T*DX，解出Y
两个Y相等，求出X。
看一下“线性代数教材”

3楼: Originally posted by 080301211 at 2015-07-14 08:42:38
大神的方法我看还可以，因为X比较简单，消Y可以，A^T*A现在是方阵，可以取逆，LZ数学太差，A^T*A或者B^T*B有没有可能逆不存在，请大神赐教。...