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´íÎóÊÇError 37 error #6633: The type of the actual argument differs from the type of the dummy argument. [S] C:\Users\zyl\Desktop\console\Console6\Console6\Source1.f90 5424 ÕâÊǵÚÒ»¸ö×Ó³ÌÐò£º SUBROUTINE BMATCH (SM,LAM,A1,A3,S,T,E,V,W,NN,LR,FLOAD,FAMP) IMPLICIT REAL*8 (A-H,O-Z) COMPLEX*16 SM(1),LAM(1),A1(1),A3(1),S(1),T(1),E(NN) COMPLEX*16 V(NN,NN),W(NN,NN),C,CC,D,DD COMPLEX*16 FLOAD(1),FAMP(1) COMMON /LRCHK/ NCOMF N1=NN-1 N2=NN-2 N3=NN-3 F=.5D0 DO 30 J=1,NN C=E(J)*(0.0D0,1.0D0) DO 30 I=1,NN 30 W(I,J)=V(I,J)*C DO 60 J=1,NN S(1)=A1(1)*W(1,J)+A3(1)*W(3,J) S(2)=A1(2)*W(2,J)+A3(2)*W(4,J) S(N1)=A1(N1)*W(N1,J)+A3(N3)*W(N3,J) S(NN)=A1(NN)*W(NN,J)+A3(N2)*W(N2,J) DO 50 I=3,N2 50 S(I)=A3(I-2)*W(I-2,J)+A1(I)*W(I,J)+A3(I)*W(I+2,J) DO 60 I=1,NN 60 W(I,J)=S(I) CALL INVERT (V,NN,NN,S,T,DET) ´íÎó¶¨Î»ÔÚÕâÒ»ÐУ¬ËµSµÄÀàÐͲ»¶Ô¡£ DO 80 I=1,NN DO 70 J=I,NN S(J)=(0.0D0,0.0D0) DO 70 K=1,NN 70 S(J)=S(J)+W(I,K)*V(K,J) DO 80 J=I,NN 80 W(I,J)=S(J) CC=(0.0D0,0.0D0) DD=(0.0D0,0.0D0) M=0 DO 100 I=2,N2,2 K=I-1 M=M+1 C=F*LAM(M) D=F*SM(M) W(K,I)=W(K,I)+C-CC W(K,K+3)=W(K,K+3)-C W(I,I+1)=W(I,I+1)-D CC=C 100 DD=D W(N1,NN)=W(N1,NN)-CC+F*LAM(M+1) DO 105 I=1,NN DO 105 J=I,NN 105 W(J,I)=W(I,J) L=0 DO 150 J=1,NN DO 150 I=1,J L=L+1 V(L,1)=W(I,J) 150 W(L,1)=V(L,1) M=0 K=-2 DO 200 I=1,NN,2 K=K+4 L=M+1 M=L+K N=L+1 DO 180 J=N,M,2 IF (NCOMF.EQ.0) GO TO 181 W(J,1)=-W(J,1) GO TO 180 181 CONTINUE V(J,1)=-V(J,1) 180 CONTINUE 200 CONTINUE READ (24) (FAMP(LK),LK=1,NN) IF (LR-2) 300,400,300 300 WRITE (23) M, (W(J,1),J=1,M) CALL FVECT(NN,FLOAD,W,FAMP) IF (LR .EQ. 3) GO TO 400 RETURN 400 WRITE (23) M, (V(J,1),J=1,M) CALL FVECT(NN,FLOAD,V,FAMP) RETURN END ÒÔÏÂÊÇ´íÎó¶¨Î»µÄÄÇÒ»Ðе÷ÓõÄ×Ó³ÌÐò£º SUBROUTINE INVERT (A,NN,N,M,C,DET) IMPLICIT REAL*8 (A-H,O-Z) DIMENSION M(1) COMPLEX*16 A(N,1),C(1),D,TEMP,DE DE=(1.0D0,0.0D0) IF (NN-1) 300,350,100 100 DO 110 I = 1,NN 110 M(I) = -I DO 200 I = 1,NN X=0.0D0 DO 130 L = 1,NN IF (M(L).GT.0) GO TO 130 DO 120 K = 1,NN IF (M(K).GT.0) GO TO 120 D=A(L,K) Y=DABS(DREAL(D))+DABS(DIMAG(D)) IF (X.GT.Y) GO TO 120 LD = L KD = K X=Y 120 CONTINUE 130 CONTINUE D=A(LD,KD) DE=DE*D L = -M(LD) M(LD) = M(KD) M(KD) = L DO 140 J = 1,NN C(J) = A(LD,J) A(LD,J) = A(KD,J) 140 A(KD,J) = C(J) DO 150 K = 1,NN 150 A(K,KD) = A(K,KD)/D DO 170 J = 1,NN IF (J.EQ.KD) GO TO 170 DO 160 K = 1,NN 160 A(K,J) = A(K,J) - C(J)*A(K,KD) 170 CONTINUE C(KD) =(-1.0D0,0.0D0) DO 180 K = 1,NN 180 A(KD,K) = -C(K)/D 200 CONTINUE DO 240 I = 1,NN L = 0 220 L = L + 1 IF (M(L).NE.I) GO TO 220 M(L) = M(I) M(I) = I DO 240 K = 1,NN TEMP = A(K,L) A(K,L) = A(K,I) 240 A(K,I) = TEMP DET=CDABS(DE) 300 RETURN 350 A(1,1) = 1.0D0/A(1,1) DET=CDABS(A(1,1)) GO TO 300 END ´íÎóÖÐÌáµ½µÄͬһ¸ö±äÁ¿ ÔÚÁ½¸ö³ÌÐòÖб»ÉùÃ÷ΪÁ½ÖÖ¸ñʽ£¬Ôõô°ì£¿ |
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3Â¥2015-06-05 11:16:48
575406210
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- ×¢²á: 2015-01-21
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2Â¥2015-06-04 14:58:53
jiangxingge
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4Â¥2015-06-05 14:42:22
jiangxingge
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- ºì»¨: 5
- Ìû×Ó: 322
- ÔÚÏß: 55.4Сʱ
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- ×¢²á: 2014-05-14
- ÐÔ±ð: GG
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