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279663962

金虫 (小有名气)

[交流] 大神们,这程序什么意思啊已有1人参与

function CirS = JacobianECT(elex,eley);

% obtain the distributions
elecfieldx(:,:,1) = elex(1,:)';
elecfieldx(:,:,2) = elex(2,:)';
elecfieldx(:,:,3) = elex(3,:)';
elecfieldx(:,:,4) = elex(4,:)';
elecfieldx(:,:,5) = elex(5,:)';
elecfieldx(:,:,6) = elex(6,:)';
elecfieldx(:,:,7) = elex(7,:)';
elecfieldx(:,:,8) = elex(8,:)';
elecfieldx(:,:,9) = elex(9,:)';
elecfieldx(:,:,10) = elex(10,:)';
elecfieldx(:,:,11) = elex(11,:)';
elecfieldx(:,:,12) = elex(12,:)';
elecfieldx(:,:,13) = elex(13,:)';
elecfieldx(:,:,14) = elex(14,:)';
elecfieldx(:,:,15) = elex(15,:)';
elecfieldx(:,:,16) = elex(16,:)';

elecfieldy(:,:,1) = eley(1,:)';
elecfieldy(:,:,2) = eley(2,:)';
elecfieldy(:,:,3) = eley(3,:)';
elecfieldy(:,:,4) = eley(4,:)';
elecfieldy(:,:,5) = eley(5,:)';
elecfieldy(:,:,6) = eley(6,:)';
elecfieldy(:,:,7) = eley(7,:)';
elecfieldy(:,:,8) = eley(8,:)';
elecfieldy(:,:,9) = eley(9,:)';
elecfieldy(:,:,10) = eley(10,:)';
elecfieldy(:,:,11) = eley(11,:)';
elecfieldy(:,:,12) = eley(12,:)';
elecfieldy(:,:,13) = eley(13,:)';
elecfieldy(:,:,14) = eley(14,:)';
elecfieldy(:,:,15) = eley(15,:)';
elecfieldy(:,:,16) = eley(16,:)';

% calculate the Sensitivity
k = 1;
% for i = 1:16
%     for j = 1:16
%         CirS(k,:) = -(elecfieldx(:,:,i).*elecfieldx(:,:,j) + elecfieldy(:,:,i).*elecfieldy(:,:,j));
%         k=k+1;
%     end
% end

for i = 1:16
    for j = i+2:i+14
        if j<17
            CirS(k,:) = -(elecfieldx(:,:,i).*elecfieldx(:,:,j) + elecfieldy(:,:,i).*elecfieldy(:,:,j));
            k=k+1;
        else
            CirS(k,:) = -(elecfieldx(:,:,i).*elecfieldx(:,:,j-16) + elecfieldy(:,:,i).*elecfieldy(:,:,j-16));
            k=k+1;
        end
    end
end
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zhangzhiguang

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小木虫: 金币+0.5, 给个红包,谢谢回帖
这应该是计算或构造CirS数组或矩阵。将获得的elex,eley这样的二维数组变成三维数组的一部分,然后通过下面的运算得到CirS数组。
好好学习,天天向上!
2楼2015-05-25 11:56:30
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279663962

金虫 (小有名气)

引用回帖:
2楼: Originally posted by zhangzhiguang at 2015-05-25 11:56:30
这应该是计算或构造CirS数组或矩阵。将获得的elex,eley这样的二维数组变成三维数组的一部分,然后通过下面的运算得到CirS数组。

3楼2015-06-30 16:18:55
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