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[求助]
一段话翻译，求助啊！
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| 把迭代阈值分割所得的二值图像G1求反得到G2，再把G1进行一次膨胀运算得到G3，用G2减去G3得到新的图像G4。在图像G4中寻找一个小面积区域，使其面积值适当，剔除组织细胞二值图像中大部分的伪区域。此处，选定区域面积值指的是图像中像素的像素值，是指像素点的大小，不是实际的区域面积值。经过分析大量的实验结果可知，选取10邻域、面积值为200的小区域剔除伪区域的效果比较理想。 |
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【答案】应助回帖
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RXMCDM: 金币+1, 多谢应助！ 2014-10-03 00:55:38
xiuzi0731(RXMCDM代发): 金币+15, 多谢应助！ 2014-11-09 10:27:36
RXMCDM: 金币+1, 多谢应助！ 2014-10-03 00:55:38
xiuzi0731(RXMCDM代发): 金币+15, 多谢应助！ 2014-11-09 10:27:36
| G2 and G3 were obtained from G1, a binary image produced by iterative threshold segmentation, by negation and dilation, respectively. A new image G4 was then obtained by subtraction of G3 from G2. A small region with an appropriate area value in image G4 was selected and most of the dummy area of the tissue and cell binary image was excluded. It should be noted that the area value in the selected region referred to pixel value rather than the actual size of the area. After analyzing a large number of experimental results, it was concluded that ideal results could be obtained by selection of 10 small neighboring regions each with an area value of 200 without dummy areas. |
2楼2014-10-02 22:54:25
