4楼: Originally posted by feixiaolin at 2014-04-21 17:09:44
有了A，numda，R，L，c的值，才可能获得 K1,K2,K3,K4,a b 的值...

2楼: Originally posted by feixiaolin at 2014-04-21 16:05:05
用节点法：
*Us(s)=Is(s)=A*numda/(s+numda)^2
Us(s)= A*numda/(s+numda)^2*sRL/(s^2*RLc+s*L+R)
    =A*numda*sRL/(s+numda)^2/(s^2*RLc+s*L+R)
    =A*numda*s/c/(s+numda)^2/(s+a)/(s+b)
    =k1/(s+numda) ...

3楼: Originally posted by linzijun789 at 2014-04-21 16:38:57
K1,K2,K3,K4,a b的值能不能具体的求出来？解得形式我能求，我能够用数学方法求出解来，但数学方法求解是那种瞬时响应不考虑延时情况，我就想知道输入信号在 RLC 电路产生延时情况下的具体解。...