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[求助]
跪求大神虫友帮忙翻译几句话!
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1.种群中的粒子在每一次更新迭代以后,都按照适应度值的大小降序排列。如果目标函数求极小值,则取适应度值较小的后一半粒子直接进入下一代(如果目标函数求极大, 则取适应度值较大的前一半粒子直接进入下一代),将剩余的粒子置于杂交池中进行遗传算法的交叉操作,生成和父代数目相同的子代,再和父代的粒子相比较,适应度值较小的后一半进入下一代,与之前直接进入下一代的粒子构成新的粒子群。 2.在以关键路线上的某一节点为起始节点和终止节点而构成的闭合圈内,所有关键调试活动的持续时间总和必须大于该圈内非关键调试活动持续时间的总和; 3.x和y分别为闭合圈内关键路线上调试活动的平均持续时间和压缩时间,a和b分别为闭合圈内非关键路线上调试活动的平均持续时间和压缩时间,c是第j个闭合圈内所有调试活动的方差的均方根,d是第个闭合圈在规定压缩水平下的常数. |
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小熊沫沫: 金币+30, 翻译EPI+1, ★★★很有帮助, GOOG! Thank you! 2014-01-06 21:29:21
小熊沫沫: 金币+20 2014-01-06 21:32:58
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1、After each update iteration, particle population are arranged in descending order according to the size of the fitness values. If the objective function obtained the minimum value , then take the fitness value smaller particles of the rear half directly into the next generation (if the objective function obtained the maximum value , then take the fitness value larger particles of the first half directly into the next generation). The remaining particles placed in a pool of hybrid genetic for crossover to generate offspring generations of the same number of the parent generations. Offspring and parent particles are compared and the smaller fitness value half particles taken into a after generation to constitute a new generation of particle swarm with direct taking into the next before. 2、In a closed circle with a node on the critical path for the start and end node , the sum time of all key commissioning activities must be greater than the sum of the circle's non-critical commissioning activities。 3、While x and y are the average duration and compression time of a closed circle on the critical path of commissioning activities ,a and b are the average duration and compression time of a closed circle of the non-critical path of commissioning activities , c is mean square variance of commissioning activities of the closure ring of the j-th , and d is the constant for the p-th closed loop under a predetermined level of compression. d是第个闭合圈在规定压缩水平下的常数.改为d是第P个闭合圈在规定压缩水平下的常数.原文是如何说的,自己核对,如有错误,敬请谅解! |

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