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feixiaolin
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cot(x/8)=cos(x/8)/sin(x/8)£» ·Ö×Ó·Öĸͬ³Ë2*cos(x/8)/*2*cos(x/4)/*2*cos(x/2)£¬ÕûÀí£¬¼´µÃ¡£ |
2Â¥2013-11-18 17:59:54
lilihurry
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3Â¥2013-11-18 22:11:36
feixiaolin
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cot(x/8)=cos(x/8)/sin(x/8)£» ·Ö×Ó·Öĸͬ³Ë2*cos(x/8)/*2*cos(x/4)/*2*cos(x/2)£¬ ÓÚÊÇ£¬cot(x/8)=(ÂÔ)/sinx£¬ cot(x/8)-cotx-3 =(ÂÔ)/sinx-cosx/sinx-3*sinx/sinx ÕûÀí£¬¼´µÃ¡£ |
4Â¥2013-11-18 22:18:03
zywang1999
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lilihurry: ½ð±Ò+5, ¡ïÓаïÖú 2013-11-19 08:55:01
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lilihurry: ½ð±Ò+5, ¡ïÓаïÖú 2013-11-19 08:55:01
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ϸһ¿´, ÃüÌâÊÇ´íÎóµÄ. ·´Àý: x=18.85ʱ, cot(x/8) - cot(x) = - 2252.8543. ¿´À´, ¾ÍÊÇԺʿҲ°ï²»ÁËÄã. ÕýÈ·µÄÃüÌâÊÇ: 0¶È<x<180¶È, cot(x/8) - cot(x) >3. Ö¤Ã÷: cot(x/8) -cotx = [8cos(x/8)*cos(x/8)*cos(x/4)*cos(x/2) - cos(x)] / sin(x) = [4(cos(x/4)+1) * cos(x/4) *cos(x/2) - 2 cos(x/2) * cos(x/2) +1] / sinx = [2cos(x/2)* (2 cos(x/4)^2 + 2cos(x/4) - cos(x/2)) + 1]/sinx = [2cos(x/2)* (1 + 2cos(x/4) ) + 1]/sinx = [sinx/sin(x/2) + sinx/sin(x/4) + 1]/sinx = 1/sin(x/2) + 1/sin(x/4) + 1/sinx > 3 (0¶È<x<180¶È) |

5Â¥2013-11-18 22:54:35
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6Â¥2013-11-22 14:33:18













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