|
|
【答案】应助回帖
★ ★ ★ ★ ★ ★ ★ ★ ★ ★
习惯萌萌: 金币+10, ★★★很有帮助, 谢谢 2013-09-17 08:22:51
第一组数据：
y1 = p1*x^p2+exp(x*p3)+p4;
y2 = p11*x^p22+exp(x*p33)+p44;
p1 -1.79746857598274
p2 1.48390927268154
p3 0.958712380423121
p4 -0.810485092529545
p11 -0.571874201360502
p22 1.33695598957879
p33 0.324717488655311
p44 -0.81048509252954
当x=0时，y1=0.189514905887667, y2=0.189514905887672
第二组数据：
y1 = p1*x^p2+exp(x*p3)+p4;
y2 = p11*x^p22+exp(x*p33)+p44;
均方差(RMSE):0.00950434758814478
残差平方和(SSE):0.00108399147691528
相关系数(R): 0.999691868598062
相关系数之平方(R^2): 0.999383832141085
确定系数(DC): 0.999383774684358
F统计(F-Statistic): -572.656421846248
参数 最佳估算
-------------------- -------------
p1 -0.34266243239571
p2 10.6205163480798
p3 -0.860141128371003
p4 -0.0803238346096522
p11 -0.565366710693137
p22 1.95859314413202E-13
p33 -0.40540714052236
p44 -0.0803238346096546
当x=0时：y1=0.919676165390348, y2=0.919676165390345 |
|
送红花一朵
回复此楼