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[ÇóÖú] Éó¸åÒâ¼û»ØÀ´ÁË£¬ÓÐÒ»ÌõÊǹØÓÚCPEÔª¼þYÊýÖµµÄµ¥Î»ÎÊÌ⣬Çë½Ì¸÷λ ÒÑÓÐ1È˲ÎÓë

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Editor's Comments:

The CPE impedance is given by Zcpe = (A^-1)((jw)^-n). The units of Z are not the same as C - they are ohm^-1 cm^-2 s^n.

Admittance Ycpe = 1/Z = A(jw)^n as you have stated. The units of Y would be the inverse those of Z, or ohm^1 cm^2 s^-n.

it is possible to determine C from Z, and several approaches have been developed:

G. J. Brug, A. L. G. van den Eeden, M. Sluyters-Rehbach, and J. H. Sluyters, J. Electroanal. Chem., 176 (1984) 275-295
C. H. Hsu, F. Mansfeld, Corrosion 57 (2001) 747-748
B. Hirschorn, M. E. Orazem, B. Tribollet, V. Vivier, I. Frateur, and M. Musiani, Electrochimica Acta, 55 (2010), 6218-6227.

In table IV you report the units of the CPE admittance as uF/cm^2. First of all, you need to use one of the above approaches to get Ccpe from Zcpe. Furthermore, those are units of capacitance determined from Z, and Y is the inverse of Z. So it is all confusing. It is better to not consider the CPE in terms of admittance. Stick to CPE impedance, Zcpe, and then determine C from Zcpe and n. Or just leave the CPE magnitude as A and use the proper units.

Also - I don't like the way you designate Y and n. Qc-Y0 and Qc-n look like differences with the dash being a minus sign. Just use Y0 and n. (or better A and n)
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