| 查看: 3365 | 回复: 5 | |||
| 当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖 | |||
[求助]
核磁信噪比
|
|||
| 核磁信噪比怎么计算？如何更准确的计算？ |
回复此楼» 收录本帖的淘帖专辑推荐
 NMR&MRI |
» 猜你喜欢
售一区SCI文章T0P，我:8O.551.O54,科目全,可十急
已经有3人回复
-
售SCI一区文章，我:8.O.551.O.5.4,科目全,可伽急
已经有3人回复
-
售SCI一区T0P文章，我:8.O55.1.O.54,科目全,可十急
已经有3人回复
-
售SCI一区T0P文章，我:8O.55.1.O.54,科目全,可伽急
已经有4人回复
-
售SCI一区T0P文章，我:8O.55.1.O.5.4,科目齐全,可+急
已经有3人回复
-
售SCI一区文章，我:8O5.5.1.O5.4,科目全,可伽急
已经有3人回复
-
售SCI一区T0P文章，我:8.O.55.1.O.5.4,科目全,可+急
已经有3人回复
-
售SCI-T0P文章，我:8O.5.5.1.O.54,科目齐全,可+急
已经有3人回复
-
售SCI一区T0P文章，我:8.O.55.1.O.5.4,科目全,可+急
已经有3人回复
-
售一区SCI文章T0P，我:8O.551.O54,科目全,可十急
已经有3人回复
【答案】应助回帖
|
In theory, signal-to-noise ratio S/N can be done in the following way. Process your spectrum, well phase it and correct the baseline. Locate the strongest peak, integrate over it, (say 0.1 ppm depending the peak width) and the integration is the signal. Now, randomly integrate over N noise regions (i.e., the non-peak regions) of 0.1 ppm wide. The average integration is the noise. signal/noise = S/N Some folks like to figure out S/N using peak height of the strongest peak and the height of the noise regions. They will run into argument of peak-to-peak or root-mean-square noise heights. |
3楼2013-07-26 04:37:12
2楼2013-07-20 10:17:31
4楼2013-07-26 09:58:51
5楼2013-07-26 11:13:48
