10楼: Originally posted by csgt0 at 2012-06-28 11:15:56
function dfw1220
clc
clear
k0=1-2^9:2^9;
ub=2^10*ones(1,2^10);
options=optimset('Algorithm','active-set');
k =fmincon(@caly,k0,[],[],[],[],[],ub,@nonlcon,options);
caly(k)
end

function y=c ...

Algorithm = LP;
Constant n=10, m=8;
Parameter For(i=1:2^n)(k[i]=[,2^n/i]);
MinFunction Sum(i=1:2^n)(k[i]*i^2);
            Sum(i=1:2^n)(k[i]*i)=2^n;
            Sum(i=1:2^n)(k[i])=2^m;

4楼: Originally posted by dingd at 2012-06-27 15:18:53
其实就是线性规划问题，求解难度不大，就是规模较大，如n=10，12和14时，求解变量达分别为：1024、4096、16384个。用1stOpt计算了n=10，m=8一组：

Algorithm = LP;
Constant n=10, m=8;
Parameter For(i=1:2^n ...

Algorithm = LP;
Constant n=10, m=8;
Parameter For(i=1:2^n)(k[i]=[,2^n/i,0]);
MinFunction Sum(i=1:2^n)(k[i]*i^2);
            Sum(i=1:2^n)(k[i]*i)=2^n;
            Sum(i=1:2^n)(k[i])=2^m;