24小时热门版块排行榜    

北京石油化工学院2026年研究生招生接收调剂公告
查看: 1189  |  回复: 2
【奖励】 本帖被评价2次,作者fangyongxinxi增加金币 1.6

fangyongxinxi

新虫 (正式写手)


[资源] 一个HF方法计算H2键长的matlab代码(一百多行)

% Downloadable MATLAB code, copyright Amritanshu Palaria
% H2 ground state from a non-relativistic Hartree Fock treatment using STO-4G basis set and Born Oppenheimer approximation  
% Program written by Amritanshu Palaria @ NCN, Apr 12, 2006
% For theoretical reference, please see "Computational Physics" by Thijssen
%  erf(x) = 2/sqrt(pi) * integral from 0 to x of exp(-t^2) dt
clear all;
% initialization
Z=1,S=1,A=0,F=0,V=0,D=0,g=0,Vecp=0,Vec=0,Val=0,EVal=0;
for y=1:41
    clear T,S,A,F,V,D,g,Vecp,Vec,Val,EVal;
    % y = 11;
    disp('Step '); disp(y);
    r = 0.45+0.05*y; % distance between nucleii in a.u.(units of a0, ie. Bohr radius)... since the problem is essentially 1-D, this is all that is needed
    disp('H-H bondlength'); disp(r);
    NNr=1/r;
    % alphas for the 4 Gaussian basis functions for each H atom
    alpha1 = [13.00773 1.962079 0.444529 0.1219492];  % sto-4g, Phi = 0.03492*exp(-13.00773*r^2)+0.2347*exp(-1.962079*r^2)+0.8138*exp(-0.444529*r^2)+1*exp(-0.1219492*r^2)
    alpha = [alpha1 alpha1];
    asize=size(alpha);
    % one H nucleus at origin, the other at r
    ra=[0 0 0 0 r r r r]; % the location of the atom with the ith basisfunction
    % first 4 basis fns come from the atom at origin
    % the next 4 come from the one at r
    % the S (overlap), T (K.E.) and A (Coulomb) matrices
    for i=1:8 % run over all basis functions
        for j=1:i % do not run over all basis functions to exploit symmetry
            % intermediate variables
            as = alpha(i)+alpha(j);
            ap = alpha(i)*alpha(j);
            rat=ap/as;
            % location of the gaussian resulting from product of
            % the 2 gaussian basis functions
            rp=(alpha(i)*ra(i)+alpha(j)*ra(j))/as;
            S(i,j)=(pi/as)^1.5*exp(-rat*(ra(i)-ra(j))^2);
            S(j,i)=S(i,j); % using symmetry
            T(i,j)=0.5*rat*(6-4*rat*(ra(i)-ra(j))^2)*S(i,j);
            T(j,i)=T(i,j); % using symmetry
            if (rp==0)
                F0=1+sqrt(pi)/2*erf(sqrt(as*(rp-r)^2))/sqrt(as*(rp-r)^2);  %  erf(x) = 2/sqrt(pi) * integral from 0 to x of exp(-t^2) dt
            elseif (rp==r)
                F0=sqrt(pi)/2*erf(sqrt(as*(rp-0)^2))/sqrt(as*(rp-0)^2)+1;
            else
                F0=sqrt(pi)/2*(erf(sqrt(as*(rp-0)^2))/sqrt(as*(rp-0)^2)+erf(sqrt(as*(rp-r)^2))/sqrt(as*(rp-r)^2));
            end
            A(i,j)=-2*pi*Z/as*exp(-rat*(ra(i)-ra(j))^2)*F0;
            A(j,i)=A(i,j); % using symmetry
        end
    end
    S
    T
    A
    [V,D]=eig(S); % gives eigenvectors in columns of V, this diagnolizes S
    for i=1:asize(2)
        V(:,i)=V(:,i)/(D(i,i)^0.5);
    end
    % the two-electron integrals P taking care of all symmetries
    % it is noted that the gaussian functions evaluate to REAL values
    % and the g operator is real and symmetric w.r.t. 1 and 2
    for i=1:8
        for j=1:i % do not run over all basis functions to exploit symmetry
            as1=alpha(i)+alpha(j);
            ap1=alpha(i)*alpha(j);
            rp=(alpha(i)*ra(i)+alpha(j)*ra(j))/as1;
            for k=1:i-1 % do not run over all basis functions to exploit symmetry
                for l=1:k % do not run over all basis functions to exploit symmetry
                    as2=alpha(k)+alpha(l);
                    ap2=alpha(k)*alpha(l);
                    rq=(alpha(k)*ra(k)+alpha(l)*ra(l))/as2;
                    if ((rp-rq)==0)
                        F0=1;
                    else
                        F0=sqrt(pi)/2*erf(sqrt(as1*as2*(rp-rq)^2/(as1+as2)))/sqrt(as1*as2*(rp-rq)^2/(as1+as2));
                    end
                    g(i,j,k,l)=2*pi^2.5/as1/as2/(as1+as2)^0.5*exp(-ap1*(ra(i)-ra(j))^2/as1-ap2*(ra(k)-ra(l))^2/as2)*F0;
                    g(k,l,i,j)=g(i,j,k,l); % using symmetry
                    g(j,i,k,l)=g(i,j,k,l); % using symmetry
                    g(i,j,l,k)=g(i,j,k,l); % using symmetry
                    g(j,i,l,k)=g(i,j,k,l); % using symmetry
                    g(k,l,j,i)=g(i,j,k,l); % using symmetry
                    g(l,k,i,j)=g(i,j,k,l); % using symmetry
                    g(l,k,j,i)=g(i,j,k,l); % using symmetry
                end
                k=i;
                for l=1:j
                    as2=alpha(k)+alpha(l);
                    ap2=alpha(k)*alpha(l);
                    rq=(alpha(k)*ra(k)+alpha(l)*ra(l))/as2;
                    if ((rp-rq)==0)
                        F0=1;
                    else
                        F0=sqrt(pi)/2*erf(sqrt(as1*as2*(rp-rq)^2/(as1+as2)))/sqrt(as1*as2*(rp-rq)^2/(as1+as2));
                    end
                    g(i,j,k,l)=2*pi^2.5/as1/as2/(as1+as2)^0.5*exp(-ap1*(ra(i)-ra(j))^2/as1-ap2*(ra(k)-ra(l))^2/as2)*F0;
                    g(k,l,i,j)=g(i,j,k,l); % using symmetry
                    g(j,i,k,l)=g(i,j,k,l); % using symmetry
                    g(i,j,l,k)=g(i,j,k,l); % using symmetry
                    g(j,i,l,k)=g(i,j,k,l); % using symmetry
                    g(k,l,j,i)=g(i,j,k,l); % using symmetry
                    g(l,k,i,j)=g(i,j,k,l); % using symmetry
                    g(l,k,j,i)=g(i,j,k,l); % using symmetry
                end
            end
        end
    end
    % Self-consistent loop
    C=ones(1,asize(2)); %initial guess, 11 行几列的1矩阵
    nor=C*S*C'   % c' 转置
    disp('Initial Guess');
    C=C/nor
    Elast=1;
    EVal=0;
    P=C'*C;
    count=0;
    rplot=-2:0.01:3; % range in atomic units (bohr) for plotting the probability density
    % figure();
    % Generating Fock matrix
    while((abs(EVal(1)-Elast))>0.000001)
        count=count+1;
        disp('Step #');
        disp(count);
        Elast=EVal(1)
        for i=1:8
            for j=1:8
                J=0;
                for k=1:8
                    for l=1:8
                        J=J+P(k,l)*g(i,j,k,l);
                    end
                end
                F(i,j)=T(i,j)+A(i,j)+J;
            end
        end
        % solve the generalized eigenvalue problem FC=ESC
        % inverse of V is its conjugate transpose because V is unitary
        Fp=V'*F*V; % modified Fock matrix
        [Vecp,Val]=eig(Fp);
        Vec=V*Vecp;
        EigVal=diag(Val,0)
        [EVal,index]=sort(EigVal);
        disp('Ground State eigenvalue from this step is (in a.u., i.e. Hartree):');
        Erec(count)=EVal(1) % lowest eigenvalue
        GrCoeff=Vec(:,index(1)); % eigenvector corresponding to ground state
        disp('C matrix from this step is:');
        C=GrCoeff.' %new C matrix, this is normalized w.r.t. S ie. C*S*C'=1
        disp('Input density matrix for next step is:');
        P=0.8*P+0.2*C'*C %new input density matrix
        GndWvFn=C(1:4)*exp(-(alpha(1:4)).'*(rplot.*rplot))+C(5:8)*exp(-(alpha(5:8)).'*((rplot-r).*(rplot-r))); % ground state wavefunction from STO-4G approximation
        %     Uncomment the next 4 lines if you need a plot of probability with step of convergence
        %     hold on;
        %     plot(rplot,(abs(GndWvFn)).^2,'r--','LineWidth',1.5);
        %     xlabel('r position');
        %     ylabel('Probability density');
        %     title('Plot of the probability density vs. r position with step of convergence');
    end
    Qs=0;
    for i=1:8
        for j=1:8
            for k=1:8
                for l=1:8
                    Qs=Qs+g(i,j,k,l)*C(i)*C(j)*C(k)*C(l);
                end
            end
        end
    end
    disp('The final total energy (including nuclear-nuclear repulsion) after convergence for this H-H bond is ');
    Eg(y)=2*C*(T+A)*C'+Qs+NNr; % the energy from h for each e, the e-e interaction and the nucleus-nucleus interaction added
    disp(Eg(y));
    if Eg(y)==min(Eg)
        rmin = r;
        Erecmin = Erec;
        WvFnmin = GndWvFn;
    end
end

figure();
plot([0.5:0.05:2.5],Eg,'bo','LineWidth',2);
title('Plot showing total energy from Hartree Fock treatment of H-H using Born Oppenheimer approximation');
xlabel('H-H bondlength');
ylabel('Total energy (in a.u.)');

disp('The least energy bond length (A) for H-H is '); disp(rmin*0.529177);
disp('The energy (Hartree) of this bond is '); disp(min(Eg));

figure();
plot(Erecmin,'ro','LineWidth',2);
axis([1 count min(Erecmin) max(Erecmin)+0.1]);
title('Plot showing convergence of Fock level with every step for the least energy H-H bondlength ');
xlabel('Step of convergence');
ylabel('Fock energy level (in a.u.)');

%plot of final probabiliy density
figure();
plot(rplot,(abs(WvFnmin)).^2,'LineWidth',2.5);
xlabel('r position');
ylabel('Probability density');
title('Plot of the probability density of electrons vs. r position for the least energy H-H bond');
axis tight;
回复此楼

» 收录本帖的淘帖专辑推荐

量化

» 猜你喜欢

» 本主题相关价值贴推荐,对您同样有帮助:

已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

anionxt

铁杆木虫 (著名写手)


★★★★★ 五星级,优秀推荐

★★★★★ 五星级
2楼2011-12-05 15:48:44
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

dhqdqk

金虫 (正式写手)


★★★★★ 五星级,优秀推荐

计算结果(matlab 2011ra X64):
The final total energy (including nuclear-nuclear repulsion) after convergence for this H-H bond is
   -1.0327

The least energy bond length (A) for H-H is
    0.7408

The energy (Hartree) of this bond is
   -1.1265

[ Last edited by dhqdqk on 2011-12-6 at 12:54 ]
3楼2011-12-06 11:53:05
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
相关版块跳转 我要订阅楼主 fangyongxinxi 的主题更新
☆ 无星级 ★ 一星级 ★★★ 三星级 ★★★★★ 五星级
普通表情 高级回复 (可上传附件)
最具人气热帖推荐 [查看全部] 作者 回/看 最后发表
[考研] 一志愿北京2,材料与化工308求调剂 +15 熊二想上岸 2026-04-04 16/800 2026-04-07 13:54 by oooqiao
[考研] 081700,311,求调剂 +17 冬十三 2026-04-04 18/900 2026-04-07 12:50 by Sammy2
[考研] 295求调剂 +18 xndjjj 2026-04-04 19/950 2026-04-07 11:02 by wangjy2002
[考研] 327求调剂 +5 Xxjc1107. 2026-04-06 5/250 2026-04-06 21:43 by dongzh2009
[考研] 第一志愿东南大学物理313,有科研竞赛获奖经历,希望物理复试调剂 +3 马内橙 2026-04-05 3/150 2026-04-06 10:32 by 蓝云思雨
[考研] 材料专硕(0856) 339分求调剂 +10 哈哈哈鹅哈哈哈 2026-04-05 10/500 2026-04-06 09:35 by jp9609
[考研] 0703求调剂383分 +9 W55j 2026-04-03 9/450 2026-04-06 06:50 by houyaoxu
[考研] 262求调剂 +7 天下第一文 2026-04-04 8/400 2026-04-05 21:31 by 激流勇渡
[考研] 求调剂 +7 张.1 2026-04-05 7/350 2026-04-05 20:40 by 啵啵啵0119
[考研] 313求调剂 +5 海日海日 2026-04-04 5/250 2026-04-05 15:52 by jndximd
[考研] 298求调剂 +7 manman511 2026-04-05 7/350 2026-04-05 10:29 by 唐沐儿
[考研] 313求调剂 +3 海日海日 2026-04-04 3/150 2026-04-05 07:48 by 544594351
[考研] 290求调剂 +7 luoziheng 2026-04-04 7/350 2026-04-04 23:17 by lqwchd
[考研] 280求调剂 +21 咕噜晓晓 2026-04-02 22/1100 2026-04-04 11:12 by 猪会飞
[考研] 考研求调剂 +3 木心想继续深造 2026-04-03 3/150 2026-04-03 21:56 by 啵啵啵0119
[考研] 一志愿重庆大学085404,总分314分,求调剂 +4 zf83hn 2026-04-03 4/200 2026-04-03 21:25 by 啵啵啵0119
[考研] 293求调剂 +5 末未mm 2026-04-02 6/300 2026-04-03 15:20 by 王保杰33
[考研] 求调剂 +3 usbdndj 2026-04-03 3/150 2026-04-03 14:10 by dxiaoxin
[考研] 能源动力 调剂 +3 不破不立0 2026-04-02 3/150 2026-04-02 12:46 by ffffjjjj
[考研] 一志愿北交大材料工程总分358 +8 cs0106 2026-04-01 9/450 2026-04-02 10:36 by 不吃魚的貓
信息提示
请填处理意见