请教一个问题,我要搞清楚程序中这两个语句的结果:
INTEGER:: k, nr,i, nodof=3,nn=96
INTEGER,ALLOCATABLE:: nf(:, : )
ALLOCATE nf(nodof,nn)
READ(10,*)nr,(k,nf(:,k),i=1,nr)
其中文件10为:
81
1 1 0 0 2 1 0 0 3 1 1 0 4 1 0 0 5 1 1 0 6 1 0 0
7 1 1 0 8 1 0 0 9 1 1 0 10 1 0 0 11 1 1 0 12 0 0 0
13 1 0 1 14 1 0 1 15 1 0 1 16 1 0 1 17 0 0 0 18 0 1 0
19 1 0 1 21 1 0 1 23 1 0 1 25 1 0 1 27 1 0 1 28 0 1 0
29 0 0 0 30 1 0 1 31 1 0 1 32 1 0 1 33 1 0 1 34 0 0 0
35 0 1 0 36 1 0 1 38 1 0 1 40 1 0 1 42 1 0 1 44 1 0 1
45 0 1 0 46 0 0 0 47 1 0 1 48 1 0 1 49 1 0 1 50 1 0 1
51 0 0 0 52 0 1 0 53 1 0 1 54 1 1 1 55 1 0 1 57 1 0 1
59 1 0 1 61 1 0 1 62 0 1 0 63 0 0 0 64 1 0 1 65 1 0 1
66 1 0 1 67 1 0 1 68 0 0 0 69 0 1 0 70 1 0 1 72 1 0 1
74 1 0 1 76 1 0 1 78 1 0 1 79 0 1 0 80 0 0 0 81 1 0 1
82 1 0 1 83 1 0 1 84 1 0 1 85 0 0 0 86 0 1 0 87 0 0 0
88 0 1 0 89 0 0 0 90 0 1 0 91 0 0 0 92 0 1 0 93 0 0 0
94 0 1 0 95 0 0 0 96 0 1 0
在debug模式下,nr值为81,k为96(?),nf是3*96的数组,i等于82(?)
能帮我解释下为什么会这样吗?非常感谢
其中nf数组前面几个值为:
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[ Last edited by li_clifff on 2011-10-15 at 00:57 ] |