| 查看: 398 | 回复: 3 | |||
| 本帖产生 1 个 翻译EPI ，点击这里进行查看 | |||
8569636.hi木虫 (正式写手)
|
[求助]
中译英润色
|
||
|
最小晶体Pb纳米粒子的直径应当是具有最高熔化温度的粒子的直径，能依据图7确定为3.75 nm ，这个值恰好位于蒋的计算结果4.64 nm 和Safaei的热力学方案值2.08 nm之间。 The diameter of the smallest crystalline Pb nanoparticles should be the one that had the highest melting temperature and can be determined as 3.75 nm according to Figure 7, which is between Jiang et al.’s calculation of 4.64 nm and Liu et al.’ thermodynamical approach of 2.08 nm. |
回复此楼» 猜你喜欢
0854复试调剂 276
已经有5人回复
-
欢迎采矿、地质、岩土、计算机、人工智能等专业的同学报考
已经有6人回复
-
0857调剂
已经有5人回复
-
279求调剂
已经有4人回复
-
284求调剂
已经有8人回复
-
材料复试调剂
已经有4人回复
-
本子写完了，给DS兄弟看了，得了92分
已经有7人回复
-
求调剂
已经有6人回复
-
材料学硕318求调剂
已经有13人回复
-
一志愿郑大材料学硕298分，求调剂
已经有5人回复
nowchenchao
金虫 (小有名气)
- 翻译EPI: 9
- 应助: 0 (幼儿园)
- 金币: 1633.5
- 散金: 35
- 帖子: 77
- 在线: 93.3小时
- 虫号: 1174524
- 注册: 2010-12-21
- 专业: 有机合成
【答案】应助回帖
★ ★
爱与雨下(金币+1): ！~ 2011-10-03 21:41:57
爱与雨下(金币+1): ！！ 2011-10-04 08:11:37
8569636.hi(金币+3): thanks! 2011-10-04 08:41:13
爱与雨下(金币+1): ！~ 2011-10-03 21:41:57
爱与雨下(金币+1): ！！ 2011-10-04 08:11:37
8569636.hi(金币+3): thanks! 2011-10-04 08:41:13
| The smallest diameter of the crystalline Pb nanoparticles should have the highest melting temperature which is 3.75 nm according to Figure 7,the value is between 4.64 nm which is calculateby Jiang et al.’s and 2.08 nm which is calculated by Liu et al.’thermodynamical approach |
2楼2011-10-03 21:37:43
nowchenchao
金虫 (小有名气)
- 翻译EPI: 9
- 应助: 0 (幼儿园)
- 金币: 1633.5
- 散金: 35
- 帖子: 77
- 在线: 93.3小时
- 虫号: 1174524
- 注册: 2010-12-21
- 专业: 有机合成
3楼2011-10-03 21:39:18
erics080
荣誉版主 (文坛精英)
- 翻译EPI: 2
- 应助: 82 (初中生)
- 贵宾: 4.325
- 金币: 48257.6
- 散金: 18655
- 红花: 123
- 沙发: 1072
- 帖子: 38213
- 在线: 2676.1小时
- 虫号: 389304
- 注册: 2007-06-01
- 专业: 高分子组装与超分子结构
- 管辖: 考博
【答案】应助回帖
★
爱与雨下(金币+1): ！~ 2011-10-04 08:11:22
8569636.hi(金币+2, 翻译EPI+1): 2011-10-04 08:40:48
爱与雨下(金币+1): ！~ 2011-10-04 08:11:22
8569636.hi(金币+2, 翻译EPI+1): 2011-10-04 08:40:48
| To agree with the diameter of nanoparticle with maximum melting temperature, the minimum diameter of the crystal Pb nanoparticles was 3.75nm from the figure 7, which is just between the value of 4.64nm, calculated by Jiang, and 2.08nm, calculated by Safaei’s thermodynamical method. |
4楼2011-10-03 22:14:49
10