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1.x£½f'(t) y=tf'(t)-f(t) Çó2½×µ¼Êý¡£ d2y/dx2 2.x=ln(1+t^2) y=t-arctan t Çó3½×µ¼Êý d3y/dx3 ×ÜÊÇËãµ½Óë´ð°¸²»Í¬£¬ÇóÖú¸÷λ´óÉñ¡£ |
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pengyehui
ľ³æ (ÕýʽдÊÖ)
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- Ó¦Öú: 15 (СѧÉú)
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- ½ð±Ò: 4215.2
- ºì»¨: 5
- Ìû×Ó: 510
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- ×¢²á: 2007-11-19
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СÓêÃÈÃÈ(½ð±Ò+1): 3Q~ 2011-08-30 14:36:30
СÓêÃÈÃÈ(½ð±Ò+1): 3Q~ 2011-08-30 14:36:30
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¸üÕý£º d3y/dx3=1/4*(-1/t2+1)*(1+t2)/(2t) |
3Â¥2011-08-29 21:38:56
pengyehui
ľ³æ (ÕýʽдÊÖ)
- ÊýѧEPI: 3
- Ó¦Öú: 15 (СѧÉú)
- ¹ó±ö: 0.03
- ½ð±Ò: 4215.2
- ºì»¨: 5
- Ìû×Ó: 510
- ÔÚÏß: 190.6Сʱ
- ³æºÅ: 462928
- ×¢²á: 2007-11-19
- ÐÔ±ð: GG
- רҵ: ¼ÆËãÊýѧÓë¿ÆÑ§¹¤³Ì¼ÆËã
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Dhwister(½ð±Ò+8): ÎÒ¶®ÁË£¬ÎÒºÜ2µØ°Ñtµ±×÷³£ÊýÁË¡£¡£¡£Ð»Ð»¡£ 2011-08-29 21:52:14
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1. dy/dx=dy/dt*dt/dx=tf''(t)*1/f''(t)=t d2y/dx2=d(dy/dx)/dt*dt/dx=1*1/f''(t)=1/f''(t) 2. dy/dx=dy/dt*dt/dx=t2/(1+t2)*(1+t2)/(2t)=t/2 d2y/dx2=d(dy/dx)/dt*dt/dx=1/2*(1+t2)/(2t)=(1+t2)/(4t) d3y/dx3=1/2*(-1/t2+1)*(1+t2)/(2t) |
2Â¥2011-08-29 21:38:19














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