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Shoney

木虫 (著名写手)


[交流] 【求助】帮忙对两个式子求导,谢谢!(已解决)

具体如附件所示,自己求得不知对不对,达人给个答案参考下,谢谢!
最后分别用dy/dt(第一个),dy/dx(第二个)表示




[ Last edited by Shoney on 2011-3-24 at 21:54 ]
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cxy1010

金虫 (小有名气)


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引用回帖:
Originally posted by Shoney at 2011-03-24 06:17:06:
具体如附件所示,自己求得不知对不对,达人给个答案参考下,谢谢!
最后分别用dy/dt(第一个),dy/dx(第二个)表示


[eimg]30/0a/435677_1300918610_634.jpg[/e ...

(1)=[img]http://latex.codecogs.com/gif.latex? \frac{\mathrm{d&space;f(t)}&space;}{\mathrm{d}&space;t}=\frac{ab(b-a)}{[(a-b)y-b]^{2}}\frac{\mathrm{dy}&space;}{\mathrm{d}&space;t} [/img]

[ Last edited by cxy1010 on 2011-3-24 at 12:03 ]
2楼2011-03-24 12:02:02
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Shoney

木虫 (著名写手)


引用回帖:
Originally posted by cxy1010 at 2011-03-24 12:02:02:
(1)=[img]http://latex.codecogs.com/gif.latex? \frac{\mathrm{d&space;f(t)}&space;}{\mathrm{d}&space;t}=\frac{ab(b-a)}{[(a-b)y-b]^{2}}\frac{\mathrm{dy}&space;}{\mathrm{d}&sp ...

跟我的不一样啊,第一个求导,分子是-ab,不是ab(b-a)
3楼2011-03-24 21:16:40
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cxy1010

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1楼

引用回帖:
Originally posted by Shoney at 2011-03-24 21:16:40:
跟我的不一样啊,第一个求导,分子是-ab,不是ab(b-a)

我是对的。你没有在对分母中的Y求导。
4楼2011-03-25 07:16:50
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