| 查看: 431 | 回复: 2 | |||
| 本帖产生 1 个 翻译EPI ,点击这里进行查看 | |||
[交流]
急求翻译
|
|||
| 我们原认为产物的结构如3a, C=N双键处于环内。产物的X-单晶衍射(图 晶体数据)却显示N(1)-C(1)的键长为1.363 Å,而N(2)-C(1)的键长为1.288 Å,比N(1)-C(1)的键长短。根据文献,C=N双键的键长为1.279 Å,而CN单键的键长为1.339 Å。因此,N(1)-C(1)实际上是单键,而N(2)-C(1)为双键,即C=N双键处于环外,结构如4a(图)。 |
» 猜你喜欢
售SCI一区文章,我:8O5.5.1.O5.4,科目全,可伽急
已经有3人回复
售SCI一区文章,我:8.O.551.O.5.4,科目全,可伽急
已经有3人回复
售SCI一区T0P文章,我:8O.55.1.O.5.4,科目齐全,可+急
已经有3人回复
售SCI文章,我:8O5.5.1.O.54,科目齐全,可+急
已经有3人回复
售SCI一区文章,我:8.O.551.O.5.4,科目全,可伽急
已经有3人回复
售SCI文章,我:8O5.5.1.O.54,科目齐全,可+急
已经有3人回复
售SCI-T0P文章,我:8O.5.5.1.O.54,科目齐全,可+急
已经有6人回复
售一区SCI文章T0P,我:8O.551.O54,科目全,可十急
已经有9人回复
售SCI-T0P文章,我:8O.5.5.1.O.54,科目齐全,可+急
已经有3人回复
考博求助
已经有3人回复
huangpeipe(金币+6, 翻译EPI+1): 说实话,不行,呵呵,给你几个金币吧,元宵节,不容易 2011-02-17 16:09:28
|
We think the product originally structure like 3a , he C=N duplet bond is in the link . The product X- unit crystal diffraction (chart crystal data) actually demonstrated that N(1)-C(1) key length is 1.363 Å ; But N(2)-C(1) key length is 1.288 Å , compares N(1)-C(1) key length. According to the literature, the C=N duplet bond's key length is 1.279 &N single bond key length is 1.339Aring; , but C Å. Therefore, N(1)-C(1) in fact is a single bond , ut N(2)-C(1) is a duplet bond, namely the C=N duplet bond is in outside the link, structure like 4a (chart). 用金山翻译的,看看行不行?行的话要小散BB哦~O(∩_∩)O~ |
2楼2011-02-17 15:53:05
huangpeipe(金币+20): 没错,只是你没看到单晶图,你要是看到就明白了,要结合图才能明白,谢谢 2011-02-19 09:30:35
|
We thought the structure of the product as shown in Figure 3a, which had C= N bond in the ring. However,it can be seen from the single crystal X-ray of products (Figure crystal data) that N (1)-C (1) bond length is 1.363 Å, and the N (2)-C (1) 1.288 Å. According to the literature, C = N bond length is 1.279 Å of while C-N bond length is 1.339 Å. Therefore, N (1)-C (1) is actually a single bond, while N (2)-C (1) is a double bond, ie C = N double bond is in the ring. The structures were shown in Figure 4a. 你的中文里面没问题吧。你说文献中单键键长是1.339 Å,而你的数据中:N(1)-C(1)的键长为1.363 Å。由此说:N(1)-C(1)实际上是单键。没弄错吧?仔细核对一下 |
3楼2011-02-18 08:41:36










回复此楼