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落日照秋草木虫 (正式写手)
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[交流]
重金求高手修改一段话！
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求达人帮忙修改一段话！ 随着X的增加，位于Y=0.5右侧的Z会逐渐向Y=0.5 的方向靠近，通道逐渐被关闭。当Z移动到位于Y=0.5的位置通道会被完全关闭，B=0。随着势的进一步增加，Z继续向远离Y=0.5 的方向移动，通道被逐渐打开B趋近于1。当有N个Z依次通过Y=0.5这点时，导致B从0到1的周期性变化，即B会随势的增加而产生准周期的振荡. With X ascending, the Z lied to the right of Y=0.5 shift to the left. The channel is generally closed. When the Z locates at Y=0.5, the channel is shut totally and B is equal to 0. As the further increase of X, the Z shift far away Y=0.5. The channel is generally reopened and the B is slowly near to 1. When several Z in turns pass the Y position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will periodically change with the increase of X. |
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落日照秋草
木虫 (正式写手)
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7楼2010-08-13 10:39:05
古可ぷ
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落日照秋草(金币+50, 翻译EPI+1):谢谢大侠拔刀相助！O(∩_∩)O 2010-08-13 08:46:50
| With the ascending of X at Y = 0.5 to the right of Z will gradually closing to the direction of Y = 0.5, the channel gradually be closed. When the Z locates at Y=0.5,the channel will be completely shut down, and B = 0.for the further increase of X, the Z will be continue movement to stay away from the direction of Y = 0.5 , then the channel was gradually opened B close to 1. When N times of Z in turns pass the position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will Quasi-periodic oscillations periodically with the increasing of X. |
2楼2010-08-12 22:16:09
落日照秋草
木虫 (正式写手)
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请高手帮忙修改下修改后的这段话！ With the ascending of X the Z on the right of the position of Y=0.5 will be gradually close to the direction of Y=0.5, the channel is gradually be closed. When the Z locates at Y=0.5, the channel will be completely shut down, and B is equal to 0. As the X further increases, the Z will move far away from the direction of Y=0.5, then the channel is gradually opened and thus B is close to 1. When several of Z in turns pass the position of Y=0.5, B periodically changes from 0 to 1, namely, B will display quasi-periodic variations with the rise of X. |
3楼2010-08-13 09:45:53
xiaoboshen
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4楼2010-08-13 10:17:56
