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落日照秋草

木虫 (正式写手)

[交流] 重金求高手修改一段话!

求达人帮忙修改一段话!

随着X的增加,位于Y=0.5右侧的Z会逐渐向Y=0.5 的方向靠近,通道逐渐被关闭。当Z移动到位于Y=0.5的位置通道会被完全关闭,B=0。随着势的进一步增加,Z继续向远离Y=0.5 的方向移动,通道被逐渐打开B趋近于1。当有N个Z依次通过Y=0.5这点时,导致B从0到1的周期性变化,即B会随势的增加而产生准周期的振荡.

With X ascending, the Z lied to the right of Y=0.5 shift to the left. The channel is generally closed. When the Z locates at Y=0.5, the channel is shut totally and B is equal to 0. As the further increase of X, the Z shift far away Y=0.5. The channel is generally reopened and the B is slowly near to 1. When several Z in turns pass the Y position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will periodically change with the increase of X.
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xiaoboshen

木虫 (小有名气)

落日照秋草(金币+10):谢谢! 2010-08-13 10:41:54
当有N个Z依次通过Y=0.5这点时,导致B从0到1的周期性变化,即B会随势的增加而产生准周期的振荡.

When several of Z in turns pass the position of Y=0.5, B periodically changes from 0 to 1, namely, B will display quasi-periodic variations with the rise of X.
When several of Z pass the point of Y=0.5 in turns, B changes periodicly from 0 to 1, that is ,B will display quasi-periodic variations with the increase of X.
最高的才能是努力!
6楼2010-08-13 10:30:19
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古可ぷ

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落日照秋草(金币+50, 翻译EPI+1):谢谢大侠拔刀相助!O(∩_∩)O 2010-08-13 08:46:50
With the ascending of X at Y = 0.5 to the right of Z will gradually closing to the direction of Y = 0.5, the channel gradually be closed. When the Z locates at Y=0.5,the channel will be completely shut down, and B = 0.for the further increase of X, the Z will be continue movement to stay away from the direction of  Y = 0.5 , then the channel was gradually opened B close to 1. When N times of Z in turns pass the position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will Quasi-periodic oscillations periodically with the increasing of X.
非吾小天下,才高而已;非吾纵古今,时赋而已;非吾睨九州,宏观而已;三非焉罪?无梦至胜
2楼2010-08-12 22:16:09
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落日照秋草

木虫 (正式写手)

请高手帮忙修改下修改后的这段话!

With the ascending of X the Z on the right of the position of Y=0.5 will be gradually close to the direction of Y=0.5, the channel is gradually be closed. When the Z locates at Y=0.5, the channel will be completely shut down, and B is equal to 0. As the X further increases, the Z will move far away from the direction of Y=0.5, then the channel is gradually opened and thus B is close to 1. When several of Z in turns pass the position of Y=0.5, B periodically changes from 0 to 1, namely, B will display quasi-periodic variations with the rise of X.
3楼2010-08-13 09:45:53
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xiaoboshen

木虫 (小有名气)

随着X的增加,位于Y=0.5右侧的Z会逐渐向Y=0.5 的方向靠近,通道逐渐被关闭。当Z移动到位于Y=0.5的位置通道会被完全关闭,B=0。

With the ascending of X, the Z on the right of Y=0.5 will  gradually close to the direction of Y=0.5, and the channel will be closed gradually, that is  B=0.
最高的才能是努力!
4楼2010-08-13 10:17:56
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