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With X ascending, the Z lied to the right of Y=0.5 shift to the left. The channel is generally closed. When the Z locates at Y=0.5, the channel is shut totally and B is equal to 0. As the further increase of X, the Z shift far away Y=0.5. The channel is generally reopened and the B is slowly near to 1. When several Z in turns pass the Y position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will periodically change with the increase of X.

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ÂäÈÕÕÕÇï²Ý(½ð±Ò+10):лл£¡ 2010-08-13 10:35:56
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With the further increasing of X, the Z will continuely move far away from the direction of Y=0.5,then the channel is gradually opened and thus B is close to 1.
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With the ascending of X at Y = 0.5 to the right of Z will gradually closing to the direction of Y = 0.5, the channel gradually be closed. When the Z locates at Y=0.5,the channel will be completely shut down, and B = 0.for the further increase of X, the Z will be continue movement to stay away from the direction of  Y = 0.5 , then the channel was gradually opened B close to 1. When N times of Z in turns pass the position of Y=0.5, the B periodically varied from 0 to 1, namely, the B will Quasi-periodic oscillations periodically with the increasing of X.
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With the ascending of X the Z on the right of the position of Y=0.5 will be gradually close to the direction of Y=0.5, the channel is gradually be closed. When the Z locates at Y=0.5, the channel will be completely shut down, and B is equal to 0. As the X further increases, the Z will move far away from the direction of Y=0.5, then the channel is gradually opened and thus B is close to 1. When several of Z in turns pass the position of Y=0.5, B periodically changes from 0 to 1, namely, B will display quasi-periodic variations with the rise of X.
3Â¥2010-08-13 09:45:53
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With the ascending of X£¬ the Z on the right of Y=0.5 will  gradually close to the direction of Y=0.5, and the channel will be closed gradually, that is  B=0.
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