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oytxtu铁杆木虫 (正式写手)
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[交流]
重金求助 修改几个逻辑关系紧密的句子
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从方程9，我们可以看到A的大小关系由B(B1/B2)决定。然而，B是与C是密切相关的根据方程3b。这也就是说明要确定B的话，我们需要先确定C1和C2。因此，我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。由于左电极宽度要小于右电极宽度，所以C1要明显小于C2。因此，B1要大于B2，i.e., B>1. One can find from Eq. (9) that the magnitude A is determined by the value of B (B=B1/B2). While the B is related to c from Eq. (3b). It indicates that to determine the value of B, one need to determine the C1 and C2 firstly. Hence, in Fig. 1 we present the C1 and C2 for an asymmetric TGNJ. Since the left terminal is narrower than the right terminal, the C1 is quite lower than the C2. Therefor the B1 is larger than B2, i.e., B>1. 这几个句子，有很多因果关系。出现的therefore, hence这类的词比较多。 希望虫友们能帮个忙，使整个小段，更流畅！ 有心的虫子，可以动动中文，但是意思不能动！ [ Last edited by oytxtu on 2010-8-8 at 09:33 ] |
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zerohead
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oytxtu(金币+30, 翻译EPI+1):感谢你的帮助，很地道 2010-08-08 23:08:44
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从方程9中，我们可以看到A的大小关系由B(B1/B2)决定。然而根据方程3b，B是与C是密切相关的。这也就是说明要确定B的话，我们需要先确定C1和C2。因此，我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。从图中我们可以清楚的看到C1要明显小于C2，这是由于左电极宽度要小于右电极宽度。因此，B1要大于B2，i.e., B>1. 我们把B的值代入方程9,我们就最终获得了A的大小关系。 From Eq. 9 it can be seen that the magnitude of A is determined from B (B=B1/B2). The magnitude of B, however, is calculated from C using Eq. 3b. In the other words, the values of C1 and C2 have to be found first before estimating the value of B. To do so, the relationship between C1 and C2 for an asymmetric TGNJ is given in Fig. 1. It shows that C1 is much smaller than C2 since the left terminal is narrower than the right one. In turn, B1 is larger than B2 with the resultant B value of larger than 1. Finally, by substituting the value of B into Eq. 9, the magnitude of A can be obtained. |
4楼2010-08-08 22:05:27
xiaoboshen
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oytxtu(金币+10):谢谢你的帮助！ 2010-08-08 23:08:59
| from Eq. (9)，we can find that the magnitude A is determined by the value of B (B=B1/B2). While the B is closely related to c from Eq. (3b). It indicates that to determine the value of B, the C1 and C2 need to be determined firstly. So we present the relationship between C1 and C2 for an asymmetric TGNJ in Fig. 1. Since the width of the left terminal is narrower than that of the right terminal, the C1 is quite lower than the C2. Therefore， the B1 is larger than B2, i.e., B>1. |
2楼2010-08-08 10:30:44
oytxtu
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3楼2010-08-08 21:37:43
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