24小时热门版块排行榜    

查看: 760  |  回复: 3
本帖产生 1 个 翻译EPI ,点击这里进行查看

oytxtu

铁杆木虫 (正式写手)

[交流] 重金求助 修改几个逻辑关系紧密的句子

从方程9,我们可以看到A的大小关系由B(B1/B2)决定。然而,B是与C是密切相关的根据方程3b。这也就是说明要确定B的话,我们需要先确定C1和C2。因此,我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。由于左电极宽度要小于右电极宽度,所以C1要明显小于C2。因此,B1要大于B2,i.e., B>1.

One can find from Eq. (9) that the magnitude A  is determined by the value of  B (B=B1/B2). While the B is related to c from Eq. (3b). It indicates that to determine the value of  B, one need to determine the C1 and C2 firstly. Hence, in Fig. 1 we present the C1  and C2 for an asymmetric TGNJ. Since the left terminal is narrower than the right terminal, the C1 is quite lower than the C2. Therefor the B1 is larger than B2, i.e., B>1.

这几个句子,有很多因果关系。出现的therefore, hence这类的词比较多。
希望虫友们能帮个忙,使整个小段,更流畅!

有心的虫子,可以动动中文,但是意思不能动!

[ Last edited by oytxtu on 2010-8-8 at 09:33 ]

» 猜你喜欢

已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

xiaoboshen

木虫 (小有名气)

oytxtu(金币+10):谢谢你的帮助! 2010-08-08 23:08:59
from Eq. (9),we can find that the magnitude A  is determined by the value of  B (B=B1/B2). While the B is closely related to c from Eq. (3b). It indicates that to determine the value of  B,  the C1 and C2 need to be determined firstly. So  we present the relationship between C1  and C2 for an asymmetric TGNJ in Fig. 1. Since the width of the left terminal is narrower than that of the right terminal, the C1 is quite lower than the C2. Therefore, the B1 is larger than B2, i.e., B>1.
最高的才能是努力!
2楼2010-08-08 10:30:44
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

oytxtu

铁杆木虫 (正式写手)

引用回帖:
Originally posted by oytxtu at 2010-08-08 09:24:43:
从方程9,我们可以看到A的大小关系由B(B1/B2)决定。然而,B是与C是密切相关的根据方程3b。这也就是说明要确定B的话,我们需要先确定C1和C2。因此,我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。由于左电极 ...

中文意思修改:

从方程9中,我们可以看到A的大小关系由B(B1/B2)决定。然而根据方程3b,B是与C是密切相关的。这也就是说明要确定B的话,我们需要先确定C1和C2。因此,我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。从图中我们可以清楚的看到C1要明显小于C2,这是由于左电极宽度要小于右电极宽度。因此,B1要大于B2,i.e., B>1. 我们把B的值代入方程9,我们就最终获得了A的大小关系。
3楼2010-08-08 21:37:43
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

zerohead

禁虫 (职业作家)

oytxtu(金币+30, 翻译EPI+1):感谢你的帮助,很地道 2010-08-08 23:08:44
从方程9中,我们可以看到A的大小关系由B(B1/B2)决定。然而根据方程3b,B是与C是密切相关的。这也就是说明要确定B的话,我们需要先确定C1和C2。因此,我们在图1里面就给出了不对称TGNJ的C1和C2之间的关系。从图中我们可以清楚的看到C1要明显小于C2,这是由于左电极宽度要小于右电极宽度。因此,B1要大于B2,i.e., B>1. 我们把B的值代入方程9,我们就最终获得了A的大小关系。

From Eq. 9 it can be seen that the magnitude of A is determined from B (B=B1/B2). The magnitude of B, however, is calculated from C using Eq. 3b. In the other words, the values of C1 and C2 have to be found first before estimating the value of B. To do so, the relationship between C1 and C2 for an asymmetric TGNJ is given in Fig. 1. It shows that C1 is much smaller than C2 since the left terminal is narrower than the right one. In turn, B1 is larger than B2 with the resultant B value of larger than 1. Finally, by substituting the value of B into Eq. 9, the magnitude of A can be obtained.
4楼2010-08-08 22:05:27
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
相关版块跳转 我要订阅楼主 oytxtu 的主题更新
普通表情 高级回复 (可上传附件)
最具人气热帖推荐 [查看全部] 作者 回/看 最后发表
[考研] 290求调剂 +6 @将就将就看 2026-03-10 11/550 2026-03-17 10:22 by @将就将就看
[考研] 285化工学硕求调剂(081700) +9 柴郡猫_ 2026-03-12 9/450 2026-03-17 10:18 by Sammy2
[考研] 211本,11408一志愿中科院277分,曾在中科院自动化所实习 +5 Losir 2026-03-12 6/300 2026-03-17 10:01 by 求调剂zz
[考研] 302求调剂 +8 负心者当诛 2026-03-11 8/400 2026-03-17 09:05 by 哦哦123
[考研] 283求调剂 +3 听风就是雨; 2026-03-16 3/150 2026-03-17 07:41 by 热情沙漠
[考研] 274求调剂 +5 时间点 2026-03-13 5/250 2026-03-17 07:34 by 热情沙漠
[基金申请] 今年的国基金是打分制吗? 50+3 zhanghaozhu 2026-03-14 3/150 2026-03-16 17:07 by 北京莱茵润色
[考研] 304求调剂 +4 ahbd 2026-03-14 4/200 2026-03-16 16:48 by 我的船我的海
[考研] 0703化学调剂,求各位老师收留 +8 秋有木北 2026-03-14 8/400 2026-03-16 15:21 by 哦哦123
[考研] 309求调剂 +5 花与叶@ 2026-03-10 5/250 2026-03-16 14:13 by 哦哦123
[考研] 326求调剂 +3 mlpqaz03 2026-03-15 3/150 2026-03-16 07:33 by Iveryant
[考研] 311求调剂 +8 zchqwer 2026-03-10 8/400 2026-03-14 00:01 by JourneyLucky
[考研] 341求调剂 +3 番茄头--- 2026-03-10 3/150 2026-03-13 23:07 by JourneyLucky
[考研] 279求调剂 +3 Dizzy123@ 2026-03-10 3/150 2026-03-13 23:02 by JourneyLucky
[考研] 一志愿西南交大,材料专硕317求调剂 +5 lx8568 2026-03-11 5/250 2026-03-13 21:43 by peike
[考研] 290求调剂 +7 ADT 2026-03-12 7/350 2026-03-13 15:17 by JourneyLucky
[考研] 0817化学工程与技术考研312分调剂 +3 T123 tt 2026-03-12 3/150 2026-03-13 10:49 by houyaoxu
[考研] 270求调剂 085600材料与化工专硕 +3 YXCT 2026-03-11 3/150 2026-03-13 10:13 by houyaoxu
[考研] 321求调剂(食品/专硕) +3 xc321 2026-03-12 6/300 2026-03-13 08:45 by xc321
[考研] 081200-11408-276学硕求调剂 +3 崔wj 2026-03-12 4/200 2026-03-12 19:33 by 求调剂zz
信息提示
请填处理意见