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化学里关于一极化曲线实验的翻译
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溶液A(溶液组成：柠檬酸钠：0．6 mol·L～)的稳态极化曲线如图l中曲线a所示．从 溶液的组成来看该曲线应为析氢稳态极化曲线，氢气的析出电势为一1．3 V 左右．在溶液A 中加入2．8×10 mol·L 的Na2SeO3，简称溶液B，溶液B的稳态极化曲线如图l中曲线b所示．曲线b形状和曲线a相似，都为一光滑的曲线，中间看不出有其它还原峰存在，说明曲线b仍为析氢稳态极化曲线；和曲线a有所不同的是：曲线b中氢气的析出电 势负移到一1．5 V左右，比未加Na2SeO3时，负移了0．2 V左右，证明Na2SeO3的加入使析氢的过电势增大了．为考察Na2SeO3是如何使析氢过电势增大的，本文首先用铁电极在锌锰共沉积电势处(一1．5V)恒电势电解溶液B 60 S，取出铁电极用二次蒸馏 水冲洗干净并以此电极为研究电极，在溶液A 中作稳态极化曲线如图l中曲线c所示．从图中可以看出：曲线C几乎和曲线b重合；而溶液A中并无Na2SeO3，说明铁电极在一1．5 V对溶液B恒电势电解时，Na2SeO。在电极上发生了电化学吸附，造成析氢过电势增加． |
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zerohead
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溶液A(溶液组成：柠檬酸钠：0．6 mol•L～)的稳态极化曲线如图l中曲线a所示．从 溶液的组成来看该曲线应为析氢稳态极化曲线，氢气的析出电势为一1．3 V 左右． The steady-state polarization curve of the solution A (0.6 mol/l sodium citrate) is shown in Figure 1 (curve a). By considering the compositions of the solution, the curve a shown in the figure is a steady-state polarization (curve) of the hydrogen evolution with a evolution potential of about 1.3V. |
2楼2010-07-24 17:33:36
lunshixiii
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xuyuan27(金币+30, 翻译EPI+1):非常感谢！ 2010-07-26 09:54:59
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Fig.4 shows the steady polarization curves of iron electrodes in Solution A, Solution B and special work electrode in Solution A (Curve A，Curve B and Curve C respectively). Solution A was composed of 100g/ L-1 (NH4)2SO4, and Solution B was added 0.1g/ L SeO2 in Solution A. To investigate whether SeO2 was adsorbed, the iron electrode was constant-potential electrolyzed 3 min in Solution B at -1.6V, removed and washed by double-distilled water. After the above series of processing, the electrode was used to make steady polarization curve in solution A which was Curve C. From the composition of the solutions, it can be concluded the curves are the steady polarization curve of hydrogen evolution. Comparing Curve B to Curve A, it is seen that with the adding of SeO2 the potential of hydrogen evolution moves from -1.3 V to -1.5V. Curve C is similar to curve B although the electrolytes are different. Therefore, SeO2 is able to take place adsorption on the cathode surface and facilitate further the hydrogen overvoltage. |
3楼2010-07-26 09:40:19
