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化学里关于一极化曲线实验的翻译
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溶液A(溶液组成:柠檬酸钠:0.6 mol·L~)的稳态极化曲线如图l中曲线a所示.从 溶液的组成来看该曲线应为析氢稳态极化曲线,氢气的析出电势为一1.3 V 左右.在溶液A 中加入2.8×10 mol·L 的Na2SeO3,简称溶液B,溶液B的稳态极化曲线如图l中曲线b所示.曲线b形状和曲线a相似,都为一光滑的曲线,中间看不出有其它还原峰存在,说明曲线b仍为析氢稳态极化曲线;和曲线a有所不同的是:曲线b中氢气的析出电 势负移到一1.5 V左右,比未加Na2SeO3时,负移了0.2 V左右,证明Na2SeO3的加入使析氢的过电势增大了.为考察Na2SeO3是如何使析氢过电势增大的,本文首先用铁电极在锌锰共沉积电势处(一1.5V)恒电势电解溶液B 60 S,取出铁电极用二次蒸馏 水冲洗干净并以此电极为研究电极,在溶液A 中作稳态极化曲线如图l中曲线c所示.从图中可以看出:曲线C几乎和曲线b重合;而溶液A中并无Na2SeO3,说明铁电极在一1.5 V对溶液B恒电势电解时,Na2SeO。在电极上发生了电化学吸附,造成析氢过电势增加. |
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zerohead
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溶液A(溶液组成:柠檬酸钠:0.6 mol•L~)的稳态极化曲线如图l中曲线a所示.从 溶液的组成来看该曲线应为析氢稳态极化曲线,氢气的析出电势为一1.3 V 左右. The steady-state polarization curve of the solution A (0.6 mol/l sodium citrate) is shown in Figure 1 (curve a). By considering the compositions of the solution, the curve a shown in the figure is a steady-state polarization (curve) of the hydrogen evolution with a evolution potential of about 1.3V. |
2楼2010-07-24 17:33:36
lunshixiii
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xuyuan27(金币+30, 翻译EPI+1):非常感谢! 2010-07-26 09:54:59
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Fig.4 shows the steady polarization curves of iron electrodes in Solution A, Solution B and special work electrode in Solution A (Curve A,Curve B and Curve C respectively). Solution A was composed of 100g/ L-1 (NH4)2SO4, and Solution B was added 0.1g/ L SeO2 in Solution A. To investigate whether SeO2 was adsorbed, the iron electrode was constant-potential electrolyzed 3 min in Solution B at -1.6V, removed and washed by double-distilled water. After the above series of processing, the electrode was used to make steady polarization curve in solution A which was Curve C. From the composition of the solutions, it can be concluded the curves are the steady polarization curve of hydrogen evolution. Comparing Curve B to Curve A, it is seen that with the adding of SeO2 the potential of hydrogen evolution moves from -1.3 V to -1.5V. Curve C is similar to curve B although the electrolytes are different. Therefore, SeO2 is able to take place adsorption on the cathode surface and facilitate further the hydrogen overvoltage. |
3楼2010-07-26 09:40:19












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