24小时热门版块排行榜

返回列表

当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖

sunxiuxin

金虫 (小有名气)

应助: 0 (幼儿园)
金币: 849.9
散金: 15
红花: 2
帖子: 62
在线: 28.9小时
虫号: 881752
注册: 2009-10-23
性别: MM
专业: 物理化学

[交流] 【求助】switch-NLO已有1人参与

最近看了几篇做配合物NLO开关的文献，文献中都有提到氧化电势和还原电势，通过比较电势的变化趋势，比如金属的氧化电势的大小，就可以推断出由于其HOMO轨道不稳定，从而使金属离子中心易于被氧化（In the previously reported series 1-4, the RuIII/II E1/2 value increases very slightly with the electron-accepting ability of R, but no corresponding trend is observed in the new series 5-7,indicating that the Ru-based HOMO is not significantly coupled to the pyd unit in these extended species. The sequential addition of electron-rich vinyl units to LA destabilizes the HOMO and makes the RuII center progressively easier to oxidize）。对这一点不太明白，为什么通过比较E就能知道金属被氧化的难易程度，是不是E值越小越容易氧化呢，还有电势的大小与配合物的NLO之间又有什么关系呢？
第二点，通过计算可以得到配合物的ΔG，利用这个ΔG是怎么计算求得E的呢，就是这段话：The free energy change associated with the reference normal hydrogen electrode halfreaction has been recalculated to be -4.36 V.33 So the reference saturated calomel electrode (SCE) should be -4.60 V. When the Nernst equation E° ) -ΔG°/nF is combined with the reference value -4.60 V, the reduction potentials
(Ecal) can be predicted.
对氧化还原有很多困惑，肯求高手指点，谢谢！

回复此楼