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lislll

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[交流] 【求助】请问这是什么错误,应该怎么办呢

算溶剂中的超极化率的
输入:
#P B3LYP/6-31+G(d,p) scrf=(pcm,read,solvent=heptane) opt freq=raman
输出错误:
Sum of APT charges=   0.09343
Electronic spatial extent (au):  =  6870.5215
Charge=     0.0000 electrons
Dipole moment (field-independent basis, Debye):
    X=    -5.8417    Y=     4.9190    Z=     0.9861  Tot=     7.7003
Quadrupole moment (field-independent basis, Debye-Ang):
   XX=   -96.3686   YY=   -96.2139   ZZ=  -108.2201
   XY=    15.3184   XZ=    -6.7202   YZ=     2.5114
Traceless Quadrupole moment (field-independent basis, Debye-Ang):
   XX=     3.8989   YY=     4.0536   ZZ=    -7.9526
   XY=    15.3184   XZ=    -6.7202   YZ=     2.5114
Octapole moment (field-independent basis, Debye-Ang**2):
  XXX=  -270.7283  YYY=    33.7609  ZZZ=     1.3308  XYY=   -31.6692
  XXY=    96.3915  XXZ=    36.6910  XZZ=    24.3936  YZZ=    -5.9211
  YYZ=     3.8234  XYZ=   -13.6207
Hexadecapole moment (field-independent basis, Debye-Ang**3):
XXXX= -7288.7432 YYYY= -1231.1423 ZZZZ=  -123.5316 XXXY=   217.1560
XXXZ=  -237.2100 YYYX=    47.6607 YYYZ=    12.9596 ZZZX=    -3.2320
ZZZY=     1.2633 XXYY= -1425.6404 XXZZ= -1388.2341 YYZZ=  -264.0511
XXYZ=    79.4926 YYXZ=   -29.4298 ZZXY=   -45.0610
N-N= 1.153333106739D+03 E-N=-4.243321297780D+03  KE= 8.248648753199D+02
  Exact polarizability: 400.936  28.095 239.785  -0.354   0.029 100.032
Approx polarizability: 500.501  56.137 372.928  -0.121  -0.306 140.661
No NMR shielding tensors so no spin-rotation constants.
Leave Link  601 at Sun Apr 25 23:45:42 2010, MaxMem=   52428800 cpu:       4.0
(Enter D:\G03W\l701.exe)
Compute integral second derivatives.
... and contract with generalized density number  0.
D1PCM: PCM CHGder 1st derivatives, ID1Alg=0 FixD1E=F DoIter=F I1PDM=0.
D2PCM: PCM 2nd derivatives, FixD2E=F I1PDM=0.
D2PCM-2 allocation failure:  iend,mxcore=  54149757  52028711
Error termination via Lnk1e in D:\G03W\l701.exe at Sun Apr 25 23:46:55 2010.
Job cpu time:  0 days 12 hours 57 minutes 48.0 seconds.
File lengths (MBytes):  RWF=    714 Int=      0 D2E=      0 Chk=     20 Scr=      1
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