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¡ï ¡ï ¡ï Сľ³æ(½ð±Ò+0.5):¸ø¸öºì°ü£¬Ð»Ð»»ØÌû½»Á÷ ratio(½ð±Ò+2):ллӦÖú£¬»¶Ó³£À´£¡ 2010-03-27 10:18
In brief, the applied voltage, E input= potential of WE vs. RE + IR drop,
when the RE is placed closed to the WE in high concentrate solution, IR drop close to 0, so E input =potential of WE vs. RE .
IF IR drop is huge, potential of WE vs. RE = E input - IR. the actual potential of WE is far away the applied potential.
For example, you ask your instrument to apply 1V at the WE, if IR drop is 0.5V, the actual potential of WE vs.RE is 0.5
this is why we have to place the RE close to the WE
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[ Last edited by xmuxiaoyu on 2010-3-29 at 05:34 ] |
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