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【求助】size 函数的用法？
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size 函数是干什么用的？ 其用法是什么？ |
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change0618
铁杆木虫 (著名写手)
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7楼2009-10-14 16:56:41
change0618
铁杆木虫 (著名写手)
方丈大师
- 应助: 44 (小学生)
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★ ★ ★
小木虫(金币+0.5):给个红包，谢谢回帖交流
kuhailangyu(金币+2,VIP+0):替楼主致谢了，呵呵 10-14 09:50
小木虫(金币+0.5):给个红包，谢谢回帖交流
kuhailangyu(金币+2,VIP+0):替楼主致谢了，呵呵 10-14 09:50
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help size SIZE Size of array. D = SIZE(X), for M-by-N matrix X, returns the two-element row vector D = [M,N] containing the number of rows and columns in the matrix. For N-D arrays, SIZE(X) returns a 1-by-N vector of dimension lengths. Trailing singleton dimensions are ignored. [M,N] = SIZE(X) for matrix X, returns the number of rows and columns in X as separate output variables. [M1,M2,M3,...,MN] = SIZE(X) for N>1 returns the sizes of the first N dimensions of the array X. If the number of output arguments N does not equal NDIMS(X), then for: N > NDIMS(X), SIZE returns ones in the "extra" variables, i.e., outputs NDIMS(X)+1 through N. N < NDIMS(X), MN contains the product of the sizes of dimensions N through NDIMS(X). M = SIZE(X,DIM) returns the length of the dimension specified by the scalar DIM. For example, SIZE(X,1) returns the number of rows. If DIM > NDIMS(X), M will be 1. When SIZE is applied to a Java array, the number of rows returned is the length of the Java array and the number of columns is always 1. When SIZE is applied to a Java array of arrays, the result describes only the top level array in the array of arrays. Example: If X = rand(2,3,4); then d = size(X) returns d = [2 3 4] [m1,m2,m3,m4] = size(X) returns m1 = 2, m2 = 3, m3 = 4, m4 = 1 [m,n] = size(X) returns m = 2, n = 12 m2 = size(X,2) returns m2 = 3 See also length, ndims, numel. |
2楼2009-10-14 09:33:41
change0618
铁杆木虫 (著名写手)
方丈大师
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3楼2009-10-14 09:34:22
4楼2009-10-14 16:37:04