| 查看: 262 | 回复: 2 | |||
| 当前主题已经存档。 | |||
andy9380金虫 (小有名气)
|
[交流]
能量转移公式的积分
|
||
| Förster resonance energy transfer中有关积分那部分的计算该如何进行? |
回复此楼» 猜你喜欢
FileCode能看出啥？
已经有23人回复
-
应该是93bebmhtak前后十一个字符比较关键
已经有36人回复
-
关于Filecode分析方法
已经有9人回复
-
2019年青年基金涵评意见，大家看看几个A，几个B?
已经有10人回复
-
不应该看fileCode
已经有6人回复
-
好奇怪的filecode
已经有6人回复
-
长年满屏的广告，版主太不责任了。基金也等的急
已经有4人回复
-
filecode
已经有15人回复
-
职称评审，求友友推荐见刊最快的期刊
已经有4人回复
-
奇怪，两个人的filecode固定段从头到尾一模一样
已经有10人回复
2楼2009-09-28 16:34:18
vjyong
木虫 (小有名气)
- 应助: 0 (幼儿园)
- 金币: 2576.5
- 帖子: 247
- 在线: 30.4小时
- 虫号: 205511
- 注册: 2006-03-03
- 性别: GG
- 专业: 无机非金属类光电信息与功
★
andy9380(金币+1,VIP+0):辛苦分 9-30 10:23
andy9380(金币+1,VIP+0):辛苦分 9-30 10:23
 where fD is the normalized donor emission spectrum, and εA is the acceptor molar extinction coefficient. κ2 =2/3 is often assumed. This value is obtained when both dyes are freely rotating and can be considered to be isotropically oriented during the excited state lifetime. If either dye is fixed or not free to rotate, then κ2 =2/3 will not be a valid assumption. In most cases, however, even modest reorientation of the dyes results in enough orientational averaging that κ2 = 2/3 does not result in a large error in the estimated energy transfer distance due to the sixth power dependence of R0 on κ2. Even when κ2 is quite different from 2/3 the error can be associated with a shift in R0 and thus determinations of changes in relative distance for a particular system are still valid. Fluorescent proteins do not reorient on a timescale that is faster than their fluorescence lifetime. In this case 0 ≤ κ2 ≤ 4. |
3楼2009-09-28 19:56:01
