| 查看: 1167 | 回复: 6 | |||
| 当前主题已经存档。 | |||
wojinjin金虫 (小有名气)
|
[交流]
【求助】多层膜反射率的计算
|
||
多层膜反射率的计算过程中,在第一个界面出射的光进入第二个界面时有个相位延迟,这个相位延迟在不同的课本上有两种表示方法,应该是说完全不同两种表述方法,有的书上是2*PI/lamata *n*d*cos(theta), theta 是折射角,lamata 是波长,而有的书上是除以 cos(theta),我认为是应该后者,各位虫友们发表下意见吧!![]() ![]() ![]() [ Last edited by wojinjin on 2009-9-10 at 18:48 ] |
» 猜你喜欢
越来越担心硕士毕业后没有竞争力了
已经有14人回复
论文的挂名怎么评判贡献?基金申请中,排名第一的挂名文章
已经有3人回复
申博自荐 2篇一区TOP+1篇EI+2公开发明专利 2027博士申请
已经有3人回复
闲聊
已经有6人回复
申博求助
已经有4人回复


2楼2009-08-18 19:18:50
3楼2009-08-20 00:46:34
4楼2009-08-22 10:09:20
5楼2009-08-24 10:22:25
freyalovers
银虫 (小有名气)
- 应助: 1 (幼儿园)
- 金币: 370.8
- 散金: 415
- 红花: 2
- 帖子: 71
- 在线: 40.9小时
- 虫号: 383583
- 注册: 2007-05-26
- 专业: 凝聚态物性 II :电子结构
6楼2009-09-10 13:06:34
★
小木虫(金币+0.5):给个红包,谢谢回帖交流
小木虫(金币+0.5):给个红包,谢谢回帖交流
|
all these two expressions are correct BUT NOT THE SAME. (using your words) An incident beam line is divided into two parts, the deflected and refracted, at an interface between the media #1 and #2. Your expression of 2*PI/lamata *n*d*cos(theta) is the TOTAL PHASE DIFFERENCE between these two beam lines in the media #1, which includes two parts, the phase lapse of the refracted beam line in media #2 (=2*PI *n*d*/[lamata*cos(theta)]), and the phase lapse of the deflected beam line in media #1 (=2*n*d*tan(theta)*sin(theta)). Therefore, the expression of 2*PI *n*d*/[lamata*cos(theta)], which you found in some other textbooks, is only a phase lapse of the refracted beam line in media #2. Sorry for making you confused in my last post. [ Last edited by bote on 2009-9-13 at 08:22 ] |
7楼2009-09-11 15:31:41











回复此楼