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seeseesea金虫 (小有名气)
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【求助完毕】帮忙翻译一段翻译起来很别扭的话
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对比表1中第4列和第6列，并结合图3，λ（TPDs-TPAs*2）除了最后一个点的P位MeO基取代外，其余各点均相对靠近0点平衡线，波动幅度也明显小于λ（TPDs-Bp）。比较λ（TPDs）与λ（TPAs）的两倍值，结果显示单体的重组能与TPDs更为接近，而且优势明显，图3中两者的最大振幅差约为0.05eV，我们认为在传输性能上单体与TPD更接近。 [ Last edited by qingshaojun0823 on 2009-9-22 at 15:44 ] |
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只是作了微修，要是按照楼上那样翻译 铁定被退。
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小木虫(金币+0.5):给个红包，谢谢回帖交流
小木虫(金币+0.5):给个红包，谢谢回帖交流
| Compare the 4th with 6th column in Table 1 and in combination with Figure 3, except for the last p-MeO substituted one, the points on λ (TPDs-TPAs * 2) are relatively close to base line and have less fluctuations than (TPDs-Bp). By Comparing the double value of λ (TPDs) with λ (TPAs), it suggests that the reorganization of the monomers are closer with TPDs, and have remarkable advantages [during reorganization]. In Figure 3, the maximum amplitude difference is about 0.05eV between the two compounds so it is believeable that the transmission performance of monomer are closer to TPD. |
7楼2009-07-08 11:19:28
seeseesea
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5楼2009-07-06 09:31:18
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etblade(金币+5,VIP+0):鼓励一下。 7-6 14:15
seeseesea(金币+4,VIP+0):谢谢你的热心帮忙 7-7 17:11
etblade(金币+5,VIP+0):鼓励一下。 7-6 14:15
seeseesea(金币+4,VIP+0):谢谢你的热心帮忙 7-7 17:11
| Compare the 4th and 6th column in Table 1 by refering to Figure 3, except the last p-MeO substituted one, the points on λ (TPDs-TPAs * 2) are relatively close to base line and have less fluctuations than (TPDs-Bp). By Comparing the double value of λ (TPDs) and λ (TPAs), it can be found that that the reorganization of the monomers are closer with TPDs, and have remarkable advantages [during reorganization]. In Figure 3, the maximum amplitude difference is about 0.05eV between two [compounds] We believe that the transmission performance of monomer are closer to TPD. |
6楼2009-07-06 13:09:20
Addiee
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8楼2009-07-22 15:08:06