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The additive loading includes among others the product of the harmonic components cos(wt) and cose( t),see Eq.(B.1).It turns out that the response period is determined from the interference of the response caused by the circular frequencies w0+ and w0- .The corresponding periods become T=2pi/ w0+ ,T=2pi/ w0- . In order to find the combined period of the response T the following ratios are evaluated T/w=n(1+2/w). The factor n is found as the minimum value at which both T tand T1 attain integer values.Poincare′maps of 2000 excitation periods are plotted in Fig.3 for various ratios of w0/ .=0.8.The amplitude is u0=0:3 m, the damping ratios c1=c2=1 and the frequency ratio w0/w1=2 Tindicate the phase value ,every excitation period T0,andeTindicates the phase value at every response period T.As seen the period tends towards infinity as w0/ .becomes irrational.As an example w0/=3:14159 results in n=314 159. For an irrational frequency ratio a so-called almost periodic response is achieved in which case a continuous closed curve is obtained in the phase plane for the Poincare′map.As seen from Fig.3 the amplitude of q1 increases as w0/ . is increased.The reason is that the fundamental blade circular eigenfrequency for the considered example is given as w0/ .=3:2125.Hence,the simulations tend towards resonance in the fundamental eigenmode as w0/ . is increased. |
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zw0912
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likefeng(金币+1,VIP+0):实在是差远了 ,不过谢谢 4-22 09:08
likefeng(金币+1,VIP+0):实在是差远了 ,不过谢谢 4-22 09:08
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载入中包括添加剂等产品的谐波成分产地来源证(重)和葡萄糖(吨) ,见均衡器。 ( B.1节) 。结果表明,该反应期间确定的干扰所造成的反应通函频率w0 +和w0 - 。相应期间成为Ť = 2pi / w0 + , Ť = 2pi / w0 - 。 为了找到合并期间的反应Ť以下比率评价Ť / W型为N ( 1 +2 / W型) 。因子n是发现的最低值都在表 t1 Ť tand实现整数values.Poincare '地图激发期间的2000年在图绘制各种比例w0 / .= 0.8.The振幅u0 = 0时03分男,阻尼比的C1 = c2 = 1和频率比w0/w1 = 2 Tindicate价值的阶段,每一个激发期间T0分离性, andeTindicates的价值在每一个阶段的反应可以看出期间吨期间趋于无穷作为w0 / 。成为irrational.As一个例子w0 / = 3:14159结果在N = 314 159 。对于不合理的频率比所谓概周期的反应是在这种情况下,实现连续封闭曲线中获得相平面的Poincare'map 。正如从图3的振幅为w0增加1季度/ 。是增大的原因是基本刀片圆形频率为审议实例作为w0 / .= 3:2125 。因此,模拟倾向于增加共振的根本振作为w0 / 。 翻得很乱,希望楼主见谅 |

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