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zaq123321

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L2 is the function space whose element's square is integrable. H1 is a sobolev space, basically the function and it's first order weak derivative are in L2.

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tzhwang03: ½ð±Ò+50, ÊÕµ½£¬Ð»Ð» 2017-09-23 14:46:45
L2 is the function space whose element's square is integrable. H1 is a sobolev space, basically the function and it's first order weak derivative are in L2.

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3Â¥2017-09-23 10:11:11
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mhhhwcf059

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4Â¥2017-09-23 12:57:02
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tzhwang03

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3Â¥: Originally posted by zaq123321 at 2017-09-23 10:11:11
L2 is the function space whose element's square is integrable. H1 is a sobolev space, basically the function and it's first order weak derivative are in L2.
...

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L2µ½µ×ÊôÓÚÕâÈýÕßÖеÄÄÄÒ»¸ö£¿¶þ£¬H1µ½µ×ÊÇsobolev ¿Õ¼ä»¹ÊÇ Hilbert¿Õ¼ä£¬Çë¸ßÊÖÖ¸½Ì£¿Èý¡¢´ÓͼƬӢÎĵıíÊöÖУ¬H1ÊÇÔõôºÍL2ÁªÏµÆðÀ´µÄ£¿Ê®·Ö¸Ðл£¬±ØÓÐÖØÐ»...
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5Â¥2017-09-23 22:42:21
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zaq123321

ר¼Ò¹ËÎÊ (ÖøÃûдÊÖ)

1. The first and the second are the same, i.e. L2. The third one, I'm not sure, whether it means the absolute value function of the second order derivative is in L2.
2. H1 is both, since it's complete inner product space, that is Hilbert space. Here H1 is also with compact support. The test function has first order weak derivative but u doesn't necessarily have. After using Greens formula, the derivative of u will go to testing function

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6Â¥2017-09-24 10:04:50
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tzhwang03

½ð³æ (ÕýʽдÊÖ)

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ÒýÓûØÌû:
6Â¥: Originally posted by zaq123321 at 2017-09-24 10:04:50
1. The first and the second are the same, i.e. L2. The third one, I'm not sure, whether it means the absolute value function of the second order derivative is in L2.
2. H1 is both, since it's comple ...

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7Â¥2017-09-24 13:35:47
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zaq123321

ר¼Ò¹ËÎÊ (ÖøÃûдÊÖ)

Doesn't matter. Thanks

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